为什么使用请求模块返回服务器代码时会遇到错误？

发布于 2025-01-31 05:45:19 字数 1515 浏览 2 评论 0原文

（我在撰写本文时使用了翻译人员。请理解，有些单词可能不正确。）我使用请求模块对其进行了测试。如果找不到该站点，则应返回404代码，但有错误。我不知道原因是什么。任何帮助将不胜感激。如何正确返回404代码？

---下面是代码。

import requests as re
a = re.get(input())
print(a.status_code)

错误： Trackback（最近的最新电话）：文件“”，第1行，在文件“ C：\ USER \ 82104_DVFQR9F \ AppData \ local \ program \ python \ python \ python310 \ lib \ lib \ site-packages \ requests \ api.py.py”，第75行，返回请求（'get'，url，params = params，** kwargs）文件“ C：\ USER \ 82104_DVFQR9F \ AppData \ local \ program \ python \ python \ python310 \ lib \ lib \ site-packages \ requests \ requests \ api.py”，第61行，返回session.request（方法=方法，url = url，** kwargs）文件“ C：\ USER \ 82104_DVFQR9F \ AppData \ local \ program \ python \ python \ python310 \ lib \ lib \ site-packages \ site-packages \ requests \ sessions.py”，第515行 prep = self.prepare_request（req）文件“ c：\ user \ 82104_dvfqr9f \ appdata \ local \ program \ python \ python \ python310 \ lib \ lib \ site-packages \ requests \ sessions \ sessions.py”，第443行， P.Prepare（文件“ c：\ user \ 82104_dvfqr9f \ appdata \ local \ program \ python \ python \ python310 \ lib \ lib \ site-packages \ request \ requests \ models.py.py”，第318行， self.prepare_url（url，params）文件“ c：\ user \ 82104_dvfqr9f \ appdata \ local \ program \ python \ python \ python310 \ lib \ lib \ site-packages \ request \ request.py.py.py”，第392行，提高错过（错误） requests.exceptions.missingschema：无效的URL'eeee.com'：没有提供计划。也许您的意思是 http://eee.com ？

原文

(I used a translator when writing this article. Please understand that some words may be incorrect.)
I tested it using the requests module. If the site cannot be found, a 404 code should be returned, but with an error. I don't know what the reason is. Any help would be appreciated. How to properly return a 404 code?

---Below is the code.

import requests as re
a = re.get(input())
print(a.status_code)

error :
Traceback (most recent call last):
File "", line 1, in
File "C:\Users\82104_dvfqr9f\AppData\Local\Programs\Python\Python310\lib\site-packages\requests\api.py", line 75, in get
return request('get', url, params=params, **kwargs)
File "C:\Users\82104_dvfqr9f\AppData\Local\Programs\Python\Python310\lib\site-packages\requests\api.py", line 61, in request
return session.request(method=method, url=url, **kwargs)
File "C:\Users\82104_dvfqr9f\AppData\Local\Programs\Python\Python310\lib\site-packages\requests\sessions.py", line 515, in request
prep = self.prepare_request(req)
File "C:\Users\82104_dvfqr9f\AppData\Local\Programs\Python\Python310\lib\site-packages\requests\sessions.py", line 443, in prepare_request
p.prepare(
File "C:\Users\82104_dvfqr9f\AppData\Local\Programs\Python\Python310\lib\site-packages\requests\models.py", line 318, in prepare
self.prepare_url(url, params)
File "C:\Users\82104_dvfqr9f\AppData\Local\Programs\Python\Python310\lib\site-packages\requests\models.py", line 392, in prepare_url
raise MissingSchema(error)
requests.exceptions.MissingSchema: Invalid URL 'eeee.com': No scheme supplied. Perhaps you meant http://eeee.com?

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没有你我更好 2025-02-07 05:45:19

您可以使用此链接用于如何使用请求模块。

import requests 
try:
   r = requests.get('https://www.google.com/search?q=ggg')
   print(r.status_code)
   if r.status_code==404:
      print("this url dosn't exist")
except Exception as error:
   print(error)

You can use this link for how to work with requests module.

import requests 
try:
   r = requests.get('https://www.google.com/search?q=ggg')
   print(r.status_code)
   if r.status_code==404:
      print("this url dosn't exist")
except Exception as error:
   print(error)

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