反向哈希猫蒙版
可以使用hashcat基于“掩码”生成字典文件,其中hashcat的论点看起来像?l?l?l?l?l?l?l?l?l?l?l?l?l? 。
其他炭是
?u = ABCDEFGHIJKLMNOPQRSTUVWXYZ
?d = 0123456789
?h = 0123456789abcdef
?H = 0123456789ABCDEF
?s = «space»!"#$%&'()*+,-./:;<=>?@[\]^_`{|}~
?a = ?l?u?d?s
?b = 0x00 - 0xff
我试图做的,在将字典文件(例如lockyou之类的)送入脚本中,它将返回前10个模式。
这可以在狂欢中完成吗?
It is possible to use hashcat to generate a dictionary file based on a "mask" where the argument for hashcat looks like ?l?l?l?l?l?l?l?l for the pattern of an 8 char all lowercase passwords.
Other charsets looks like
?u = ABCDEFGHIJKLMNOPQRSTUVWXYZ
?d = 0123456789
?h = 0123456789abcdef
?H = 0123456789ABCDEF
?s = «space»!"#$%&'()*+,-./:;<=>?@[\]^_`{|}~
?a = ?l?u?d?s
?b = 0x00 - 0xff
I'm trying to do the opposite where I feed a dictionary file (like rockyou or something) into the script, and it will return the top 10 patterns.
Can this be done in bash?
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statsgen
来自 pack toolkit 如果您将通过频率将蒙版保存到文件中,如果您使用其-O [OUTFILE]
选项。statsgen
from the PACK toolkit will save masks by frequency to a file if you use its-o [outfile]
option.