python名为tuple：attributeError：＆＃x27; tuple＆＃x27;对象没有属性＆＃x27; end_pos＆＃x27;
我的课程开始如下：
from collections import namedtuple
class Parser:
Rule = namedtuple('Rule', ['lhs', 'rhs', 'dot_pos', 'start_pos', 'end_pos'])
# __init__ ...
由于Pycharm通过给我适当的建议正确地检测到了我所有的元组元素命名，所以我以为我以正确的方式做到了，创建一个小rule如上所示。
现在，我在Parser类中有一个方法，该类别rule参数：
def add(self, dot_rule: Rule):
print(dot_rule.end_pos)
# ...
不幸的是，一旦我尝试调用dot_rule dot_rule <的元素，以下错误就会出现。 /code>喜欢end_pos：
attributeError：'tuple'对象没有属性'end_pos'
在使用nequ> nequ> nequ> nequ> nation>
编辑：我调用方法添加 lhs，RHS和pos pos 代码>是提前计算的一些值：
self.add（（LHS，RHS，0，POS，POS）））
我想，因为据说nequ> 元组这将是正确的语法。显然，该参数现在被视为普通元组，而不是Rule。我在这里可以做什么？
编辑2：追溯消息：
Traceback (most recent call last):
File "...\earley.py", line 19, in <module>
main()
File "...\earley.py", line 14, in main
parser = Parser(grammar, lexicon, sentence)
File "...\parser.py", line 21, in __init__
self.parse(sentence)
File "...\parser.py", line 56, in parse
self.predict('S', i)
File "...\parser.py", line 41, in predict
self.add((lhs, rhs, 0, pos, pos)) # (X -> .α, i, i)
File "...\parser.py", line 24, in add
print(dot_rule.end_pos)
AttributeError: 'tuple' object has no attribute 'end_pos'
I have a class that starts as follows:
from collections import namedtuple
class Parser:
Rule = namedtuple('Rule', ['lhs', 'rhs', 'dot_pos', 'start_pos', 'end_pos'])
# __init__ ...
Since PyCharm detected all my tuple element namings correctly by giving me proper suggestions, I assumed I did it the right way so far, creating a little Rule class with the syntax shown above.
Now, I have a method within my Parser class that takes a Rule parameter:
def add(self, dot_rule: Rule):
print(dot_rule.end_pos)
# ...
Unfortunately, following error appears as soon as I try to call an element of dot_rule like end_pos:
AttributeError: 'tuple' object has no attribute 'end_pos'
What is it that I misunderstood when using namedtuple?
Edit: I call the method add the following way with lhs, rhs, and pos being some values calculated beforehand:
self.add((lhs, rhs, 0, pos, pos))
I thought since namedtuple is said to be backward-compatible with tuple this would be the correct syntax. Apparently, the parameter is now seen as a plain tuple instead of a Rule. What can I do differently here?
Edit 2: Traceback message:
Traceback (most recent call last):
File "...\earley.py", line 19, in <module>
main()
File "...\earley.py", line 14, in main
parser = Parser(grammar, lexicon, sentence)
File "...\parser.py", line 21, in __init__
self.parse(sentence)
File "...\parser.py", line 56, in parse
self.predict('S', i)
File "...\parser.py", line 41, in predict
self.add((lhs, rhs, 0, pos, pos)) # (X -> .α, i, i)
File "...\parser.py", line 24, in add
print(dot_rule.end_pos)
AttributeError: 'tuple' object has no attribute 'end_pos'
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您可以尝试一下：从本质上讲，您将其传递给了一个类元组，而不是称为规则的 nationtuple 。请参阅：
而不是
self.add（（LHS，RHS，0，POS，POS）））使用
self.add（解析器） .rule（LHS，RHS，0，POS，POS））You can try this: essentially you were passing it a class tuple instead of the namedtuple called Rule. See:
Instead of
self.add((lhs, rhs, 0, pos, pos))Use
self.add(Parser.Rule(lhs, rhs, 0, pos, pos))