如何计数名称java的数量

发布于 2025-01-31 05:39:31 字数 1060 浏览 4 评论 0原文

嗨，大家好。我是Java的新手，目前正在学习字符串。

我有一个任务来计算名称的数量，名称的长度必须至少两个，名称的第一个字母应从上案例开始，第二个字母为较低的情况。

问题是我不知道如何使用字符。Isuppercase（text.charat（i））和targin.islowercase（text.Charat（i + 1））。

我会使用一些建议或提示。

class NameCounterTest {
    public static void main(String[] args) {
        // 1
        System.out.println(new NameCounter().count("Mars is great planet"));

        // 2
        System.out.println(new NameCounter().count("Moon is near Earth"));

        // 0
        System.out.println(new NameCounter().count("SPACE IS GREAT"));
    }
}

class NameCounter {
    public int count(String text) {
        String[] words = text.split(" ");

        int wordLength = 0, counter = 0;

        for (int i = 0; i < words.length; i++) {
            String word = words[i];
            wordLength = word.length();

            if (wordLength >= 2 && Character.isUpperCase(text.charAt(i)))
                counter++;
        }
        return counter;
    }
}

Output:
1; //Should be 1;
1; //Should be 2;
3; //Should be 0;

原文

Hi guys.
I'm new to Java, currently learning Strings.

I have a task to count the number of names, the length of the name must be at least two, the first letter of the name should start with upper case, the second with lower case.

The issue is that I don't know how to use the Character.isUpperCase(text.charAt(i)) and Character.isLowerCase(text.charAt(i + 1)) in the same if.

I would use some advice or hint.

class NameCounterTest {
    public static void main(String[] args) {
        // 1
        System.out.println(new NameCounter().count("Mars is great planet"));

        // 2
        System.out.println(new NameCounter().count("Moon is near Earth"));

        // 0
        System.out.println(new NameCounter().count("SPACE IS GREAT"));
    }
}

class NameCounter {
    public int count(String text) {
        String[] words = text.split(" ");

        int wordLength = 0, counter = 0;

        for (int i = 0; i < words.length; i++) {
            String word = words[i];
            wordLength = word.length();

            if (wordLength >= 2 && Character.isUpperCase(text.charAt(i)))
                counter++;
        }
        return counter;
    }
}

Output:
1; //Should be 1;
1; //Should be 2;
3; //Should be 0;

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掩饰不了的爱 2025-02-07 05:39:31

您可以使用Word.Charat（0）和Word.Charat（1）以获取循环中每个单词中的第一个和第二个字符。

class NameCounterTest {
    public static void main(String[] args) {
        // 1
        System.out.println(new NameCounter().count("Mars is great planet"));

        // 2
        System.out.println(new NameCounter().count("Moon is near Earth"));

        // 0
        System.out.println(new NameCounter().count("SPACE IS GREAT"));
    }
}

class NameCounter {
    public int count(String text) {
        String[] words = text.split(" ");

        int wordLength = 0, counter = 0;

        for (int i = 0; i < words.length; i++) {
            String word = words[i];
            wordLength = word.length();

            if (wordLength >= 2 && Character.isUpperCase(word.charAt(0)) && Character.isLowerCase(word.charAt(1)))
                counter++;
        }
        return counter;
    }
}

You can use word.charAt(0) and word.charAt(1) to get the first and second character in each word in the loop.

class NameCounterTest {
    public static void main(String[] args) {
        // 1
        System.out.println(new NameCounter().count("Mars is great planet"));

        // 2
        System.out.println(new NameCounter().count("Moon is near Earth"));

        // 0
        System.out.println(new NameCounter().count("SPACE IS GREAT"));
    }
}

class NameCounter {
    public int count(String text) {
        String[] words = text.split(" ");

        int wordLength = 0, counter = 0;

        for (int i = 0; i < words.length; i++) {
            String word = words[i];
            wordLength = word.length();

            if (wordLength >= 2 && Character.isUpperCase(word.charAt(0)) && Character.isLowerCase(word.charAt(1)))
                counter++;
        }
        return counter;
    }
}

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