将列表与外部浮子乘以循环

Question

我有一个清单，包括工人的工资 我想给他们50％的加薪，所以我想将清单乘以1.5 这是我的代码：

wages = [100, 150, 180, 250, 400]
for i in range(0,5):
    print("Previous wage for ", i, "was: ", wages[i])
    wages = [i * 1.5 for i in wages]
    print("New wage for ", i, "is", wages[i])

但是，这是我得到的结果：

Previous wage for  0 was:  100
New wage for  0 is 150.0
Previous wage for  1 was:  225.0
New wage for  1 is 337.5
Previous wage for  2 was:  405.0
New wage for  2 is 607.5
Previous wage for  3 was:  843.75
New wage for  3 is 1265.625
Previous wage for  4 was:  2025.0
New wage for  4 is 3037.5

第一批工资是正确的，但是随后它开始给出我不想要的结果。像指数的工资[1]应该是150个以前的和225个新....

我弄错了，请协助

Answer 1

在循环的每一个迭代中，您将整个列表乘以1.5。您也可以将其更改为仅在您要迭代的索引处乘以。

wages = [100, 150, 180, 250, 400]
for i in range(len(wages)):
    print("Previous wage for ", i, "was: ", wages[i])
    wages[i] *= 1.5
    print("New wage for ", i, "is", wages[i])

或使用列表理解一次。

wages = [100, 150, 180, 250, 400]
new_wages = [wage * 1.5 for wage in wages]
for i in range(len(wages)):
    print("Previous wage for ", i, "was: ", wages[i])
    print("New wage for ", i, "is", new_wages[i])

带有列表理解的语句乘以 Wages列表中的所有按1.5分配给new_wages。 new_wages IS [150.0，225.0，270.0，375.0，600.0]分配后。

编辑：
根据@Mad物理学家的评论，您应该避免将硬编码数字纳入您的代码中。因此，与其在range函数中具有5个，不如使用len（），因此在您从列表中添加或删除数字后起作用。