在python中分别进行每个函数调用外,请尝试尝试
我有此代码:
def print_trained_network(trained_network):
print("Accuracy on training set:", trained_network['score_training'])
print("Accuracy on test set:", trained_network['score_test'])
print("Execution time", trained_network['time_elapsed'])
print("Best loss", trained_network['best_loss'])
print("n_iter", trained_network['n_iter'])
print("train_shape", trained_network['train_shape'])
try:
print("label", trained_network['label'])
except:
pass
我想尝试在试验中运行每个打印呼叫,除了最后一个呼叫,而不必添加更多的行,而不必添加更多的行,而是用Try Catch Block包围。
有办法做到吗?
I have this code:
def print_trained_network(trained_network):
print("Accuracy on training set:", trained_network['score_training'])
print("Accuracy on test set:", trained_network['score_test'])
print("Execution time", trained_network['time_elapsed'])
print("Best loss", trained_network['best_loss'])
print("n_iter", trained_network['n_iter'])
print("train_shape", trained_network['train_shape'])
try:
print("label", trained_network['label'])
except:
pass
I want to run every print call in a try except pass, like the last one, without having to add many more lines, by surrounding each with the try catch block.
Is there a way to do it?
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对于您的问题,我想不出一个“漂亮”解决方案。但这是我如何解决这个问题的工作示例。
输出:
I can't think of a "pretty" solution for your problem. But this is a working example of how I would solve that.
Output: