如何在Java中发布请求以在JSON中获取响应

Question

我想以同一构造发布该请求。

    POST /mga/sps/oauth/oauth20/token HTTP/1.1
    Host: example.com
    Content-Type: application/x-www-form-urlencoded
    Authorization: Basic aaabbbCCCdddeeefffGGG
    client_id=xxx&client_secret=yyy&grant_type=authorization_code
    &code=3v6MJzt9vKtRkxpTFnkJG3IyspWC2k
    &redirect_uri=xyz%2Ffolder

我已经实施了，但得到了不良的请求，无法打印帖子内容，我在发送此请求后也想获得JSON响应。

String urlParameters  = "grant_type=authorization_code"+"&redirect_uri="+session.getAttribute("redirect_uri")+"&code_verifier="+session.getAttribute("codeVerifier")+"&code="+session.getAttribute("code")+"&state="+session.getAttribute("state");
        byte[] postData = urlParameters.getBytes( StandardCharsets.UTF_8 );
        int postDataLength = postData.length;
        URL url = new URL( "https://example/oauth20/token" );
        HttpURLConnection conn= (HttpURLConnection) url.openConnection();           
        conn.setDoOutput(true);
        conn.setInstanceFollowRedirects(false);
        conn.setRequestMethod("POST");
     
        conn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded"); 
        conn.setRequestProperty("charset", "utf-8");
        conn.setRequestProperty("Content-Length", 
       Integer.toString(postDataLength ));
        conn.setRequestProperty("Host","example.com");
        conn.setRequestProperty("Authorization","clientID=xyz");
        conn.setUseCaches(false);
        DataOutputStream wr = new 
       DataOutputStream(conn.getOutputStream());
        wr.write(postData);
        System.out.println(conn.getResponseCode());
        System.out.println(conn.getResponseMessage());
        conn.disconnect();

 

Answer 1

您有多个选项。

1. 您可以从 java http client -

在Java 11中添加了HTTP客户端。它可用于请求HTTP
通过网络的资源。它支持HTTP/1.1和HTTP/2
同步和异步编程模型，处理请求和
响应体作为反应性流，并遵循熟悉的建筑商
模式。

2. apache httpclient -
   

3. > RESTTEMPLATE - 参考

4. jax-rs client - 示例

5. Spring 5 webclient - 示例

6. okhttpclient - 示例

比较