如何编写SQL查询来通过排除克隆交付取消来获取已完成和取消交付的数量？

发布于 2025-01-30 17:31:35 字数 1168 浏览 2 评论 0原文

id	送达	parentid	状态
1	parentdelivery1	0	取消
2	词	1	取消
3	1b	1	完成
个	clonedelivery1c	1	取消
5	parentDelivery2	0	取消
4	Clonedelivery2A	6	typertype
1a	克隆	5
		词
克隆

这个示例）：

已完成交付的	已完成交货数量的
数量2	2

所有父送货都有0，作为父级和克隆送货在这里，如果完成了父母和克隆的1次交付，则应将其算作完成，并且应取消所有克隆的取消。
*父送货员可以有0个克隆
*克隆交付不会有自己的克隆
*如果取消父母的送达，但其克隆的任何1个都已完成，则应将其视为1件完成，并取消0（其他取消的取消，不应在取消的交货中计数

）应计算为1个取消。如何为此编写SQL查询？

我正在使用MySQL Workbench社区版本8.0.29

原文

Id	deliverytype	parentId	status
1	parentDelivery1	0	cancelled
2	cloneDelivery1a	1	cancelled
3	cloneDelivery1b	1	completed
4	cloneDelivery1c	1	cancelled
5	parentDelivery2	0	cancelled
6	cloneDelivery2a	5	cancelled
7	cloneDelivery2b	5	cancelled
8	cloneDelivery 2c	5	cancelled
9	parentDelivery3	0	completed
10	parentDelivery4	0	cancelled

expected output(for this example):

number of completed deliveries	number of cancelled deliveries
2	2

All parent deliveries have 0 as parent id and clone deliveries have its parentId in parentId column
Here if even 1 delivery out of parent and clones is completed then it should count as completed and all clone cancellation should be eliminated.
*Parent deliveries can have 0 clones
*Clone deliveries will not have clone of its own
*If Parent delivery is cancelled but any 1 of its clone is completed then it should be considered as 1 completed and 0 cancelled(the other cancellations should not be counted under cancelled deliveries)

If all the delivery out of parent and clones is cancelled then it should be counted as 1 cancellation. How can I write an SQL query for this?

I am using MySQL workbench community version 8.0.29

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鼻尖触碰 2025-02-06 17:31:35

我的释义逻辑...

如果父母说完成了，
如果父母说取消了，但任何孩子都说完成了，它完成了，
否则，父母和所有孩子都说取消了，所以它被取消了，

这给了...

WITH
  parent_outcome AS
(
  SELECT
    p.id,
    CASE
      WHEN MAX(p.status) = 'completed' THEN 1
      WHEN MAX(c.status) = 'completed' THEN 1
      ELSE 0
    END
      AS is_completed
  FROM
    your_table AS p
  LEFT JOIN
    your_table AS c
       ON c.parent_id = p.id
  WHERE
    p.parent_id = 0
  GROUP BY
    p.id
)
SELECT
             SUM(is_completed) AS is_completed,
  COUNT(*) - SUM(is_completed) AS is_cancelled
FROM
  parent_outcome

My paraphrased logic...

if the parent says completed, it is completed
if parent says cancelled, but any children say completed, it is completed
else, parent and all children say cancelled, so it is cancelled

Which gives...

WITH
  parent_outcome AS
(
  SELECT
    p.id,
    CASE
      WHEN MAX(p.status) = 'completed' THEN 1
      WHEN MAX(c.status) = 'completed' THEN 1
      ELSE 0
    END
      AS is_completed
  FROM
    your_table AS p
  LEFT JOIN
    your_table AS c
       ON c.parent_id = p.id
  WHERE
    p.parent_id = 0
  GROUP BY
    p.id
)
SELECT
             SUM(is_completed) AS is_completed,
  COUNT(*) - SUM(is_completed) AS is_cancelled
FROM
  parent_outcome

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