Python打印整个URL
我正在尝试拉出所有包含“ https://play.google.com/store/”的URL并打印整个字符串。当我运行当前代码时，它只打印“ https://play.google.com/store/”，但我正在寻找整个URL。有人可以将我指向正确的方向吗？这是我的代码：
import pandas as pd
import os
import requests
from bs4 import BeautifulSoup
import re
URL = "https://www.pocketgamer.com/android/best-tycoon-games-android/?page=3"
page = requests.get(URL)
soup = BeautifulSoup(page.text, "html.parser")
links = []
for link in soup.findAll("a", target="_blank"):
links.append(link.get('href'))
x = re.findall("https://play.google.com/store/", str(links))
print(x)
I am trying to pull all the urls that contain "https://play.google.com/store/" and print the entire string. When I run my current code, it only prints "https://play.google.com/store/" but I am looking for the entire URL. Can someone point me in the right direction? Here is my code:
import pandas as pd
import os
import requests
from bs4 import BeautifulSoup
import re
URL = "https://www.pocketgamer.com/android/best-tycoon-games-android/?page=3"
page = requests.get(URL)
soup = BeautifulSoup(page.text, "html.parser")
links = []
for link in soup.findAll("a", target="_blank"):
links.append(link.get('href'))
x = re.findall("https://play.google.com/store/", str(links))
print(x)
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评论（1）
re.findall只是返回与正则符合正则匹配的文本的一部分，因此您要获得的只是https://play.google.com/store/是在正则。您可以修改正则表达式，但是鉴于您要搜索的内容是链接列表，只需检查它们是否以https://play.google.com/store/开始。例如：输出（用于查询）：
re.findalljust returns the part of the text that matches the regex, so all you are getting is thehttps://play.google.com/store/that is in the regex. You could modify the regex, but given what you are searching is a list of links, it's easier to just check if they start withhttps://play.google.com/store/. For example:Output (for your query):