嘲笑Java接口中的方法时与Mockito的问题

Question

使用Junit5和Mockito 3.8嘲笑Java接口中的方法时，我有问题。该测试失败了：

Wanted but not invoked:
remoteCommands.getServiceStatus("ABC");
-> at com.acme.CommandHandlerTest.testServiceName(CommandHandlerTest.java:40)
Actually, there were zero interactions with this mock.

它在CommandHandlertest.java的40行失败，但是

verify(remoteCommands).getServiceStatus(serviceName);

，当我调试代码时，我可以看到正在执行的方法，因此我知道与此方法有1个相互作用，但Mockito无法识别它。

请建议我是否缺少什么？我的代码文件如下，

commandhandlertest.java

package com.acme;

import static org.mockito.ArgumentMatchers.eq;
import static org.mockito.Mockito.verify;
import static org.mockito.Mockito.when;

import java.rmi.RemoteException;

import org.junit.jupiter.api.BeforeEach;
import org.junit.jupiter.api.Test;
import org.junit.jupiter.api.extension.ExtendWith;
import org.mockito.Mock;
import org.mockito.MockitoAnnotations;
import org.mockito.junit.jupiter.MockitoExtension;

@ExtendWith(MockitoExtension.class)
public class  CommandHandlerTest {

    private CommandHandler commandHandler;
    
    @Mock
    IRemoteCommandsImpl remoteCommands;
    
    @BeforeEach
    void setup() {
        MockitoAnnotations.openMocks(this);
    }

    @Test
    void testDoCommand_serviceName() throws RemoteException {
        commandHandler = new CommandHandler();
        
        String serviceName = "ABC";
        int mockValue = 4000;

        when(remoteCommands.getServiceStatus(eq(serviceName))).thenReturn(mockValue);
        
        commandHandler.printServiceStatus(serviceName);
        
        verify(remoteCommands).getServiceStatus(serviceName);
        
    }
}

commandhandler.java

package com.acme;

public class CommandHandler {

    private IRemoteCommands remoteCommands;
    
    public CommandHandler(){

    }

    public void printServiceStatus(String service) {

        remoteCommands = new IRemoteCommandsImpl();
        int serviceStatus = 0;

        try {
            serviceStatus = remoteCommands.getServiceStatus(service);
            System.out.println("CommandHandler->serviceStatus: "+serviceStatus);
        } catch (Exception e) {
            e.getMessage();
        }
    }
}

iremotecommands.java

package com.acme;
import java.rmi.Remote;
import java.rmi.RemoteException;

public interface IRemoteCommands extends Remote
{

    public int getServiceStatus(String serviceName) throws RemoteException;

}

iremotecommandsimpl.java

package com.acme;
import java.rmi.RemoteException;

public class IRemoteCommandsImpl implements IRemoteCommands{

    @Override
    public int getServiceStatus(String serviceName) throws RemoteException {
        return 1000;
    }
}

Answer 1

在您的CommandHandler中，您创建了一个新实例iRemoteCommandSimpl，然后将其分配给private remotecommands字段。

这意味着您模拟的remoteCommands未经测试的对象未使用。

您需要重组代码，并提供remoteCommands commandhandler ，最好是通过构造函数：

public class CommandHandler {

    private final IRemoteCommands remoteCommands;
    
    public CommandHandler(IRemoteCommands remoteCommands) {
        this.remoteCommands = remoteCommands;
    }
    // ...
}

最重要的是：

• 您不需要opoceToantoAnnotations.openmocks（this）; 如果您使用MockItoextension