start -process -passThru无法抓住流程ID吗？

发布于 2025-01-30 11:53:41 字数 644 浏览 7 评论 0原文

我有一个PowerShell脚本，可以通过start -Process $ type -passthru通过返回的PID打开和关闭.txt .exe .exe 。但是，如果我尝试使用.png s做同样的事情，我会得到此错误：

start-process：由于系统无法找到所需的所有信息，因此无法完全运行此命令。

我正在尝试获得返回的PID，以便我可以关闭默认的照片编辑器，而无需按名称明确调用。代码样本：

$object = Get-ChildItem | Where-Object {$_.LastWriteTime -gt (Get-Date).AddDays(-730)} | Select-Object -Property Name  
[System.Collections.ArrayList] $filearray = $object 
$removed = $filearray[-1].Name
$open_photo = Start-Process -FilePath $removed -passthru 
$open_photo.Id

原文

I have a PowerShell script able to open and close .txt and .exe via a returned PID from Start-process $type -Passthru. However, if I try to do this same thing with .pngs I get this error:

Start-Process : This command cannot be run completely because the system cannot find all the information required.

I am trying to get a returned PID so I can close the default photo editor without having to explicitly call it by name. Code sample:

$object = Get-ChildItem | Where-Object {$_.LastWriteTime -gt (Get-Date).AddDays(-730)} | Select-Object -Property Name  
[System.Collections.ArrayList] $filearray = $object 
$removed = $filearray[-1].Name
$open_photo = Start-Process -FilePath $removed -passthru 
$open_photo.Id

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