始终调用函数而无需重复使用Guard子句的函数的代码的方法

发布于 2025-01-30 05:47:47 字数 548 浏览 2 评论 0原文

我有一个看起来像这样的函数：

function myFunc(){
  if (!condition1){
    //some extra code (diff. from condition2 if-statement)
    doSomething();
    return;
  }
  if (!condition2){
    //some extra code (diff. from condition1 if-statement)
    doSomething();
    return;
  }
  //some extra code (diff. from both condition if-statement)
  doSomething();
}

我想知道是否有一种简化此代码的方法，因此函数dosomething（）始终执行（例如，在Java中使用try/catch/最后）。

原文

I have a function which looks like this:

function myFunc(){
  if (!condition1){
    //some extra code (diff. from condition2 if-statement)
    doSomething();
    return;
  }
  if (!condition2){
    //some extra code (diff. from condition1 if-statement)
    doSomething();
    return;
  }
  //some extra code (diff. from both condition if-statement)
  doSomething();
}

I would like to know if there is a way to simplify this code so the function doSomething() always execute (like in Java with try/catch/finally).

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月依秋水 2025-02-06 05:47:47

使用尝试/捕获[可选]/最后解决了我的问题。

try {
  (function myFunc(){
    if (!condition1){
      //some extra code (diff. from condition2 if-statement)
      return;
    }
    if (!condition2){
      //some extra code (diff. from condition1 if-statement)
      return;
    }
    //some extra code (diff. from both condition if-statement)
  })();
} finally {
  doSomething();
}

Using try/catch[optional]/finally solved my problem.

try {
  (function myFunc(){
    if (!condition1){
      //some extra code (diff. from condition2 if-statement)
      return;
    }
    if (!condition2){
      //some extra code (diff. from condition1 if-statement)
      return;
    }
    //some extra code (diff. from both condition if-statement)
  })();
} finally {
  doSomething();
}

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