检查字符串是否仅包含日期，没有时间戳

发布于 2025-01-30 04:18:16 字数 327 浏览 2 评论 0原文

我试图检测字符串是否包含没有时间戳的日期。日期和时间戳可以采用不同的格式。

我尝试用Python-dateutil解析字符串，但它返回包含时间戳的DateTime实例。

import dateutil.parser

print(dateutil.parser.parse("2020-01-01"))
print(dateutil.parser.parse("2020-01-01 01:24:37 UTC"))

2020-01-01 00:00:00
2020-01-01 01:24:37+00:00

原文

I am trying to detect if a string contains a date without a timestamp. The date and timestamp can be in different formats.

I tried parsing the strings with python-dateutil, but it returns a datetime instance which contains a timestamp.

import dateutil.parser

print(dateutil.parser.parse("2020-01-01"))
print(dateutil.parser.parse("2020-01-01 01:24:37 UTC"))

returns

2020-01-01 00:00:00
2020-01-01 01:24:37+00:00

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不奢求什么 2025-02-06 04:18:16

您可以将REGEX用于此目的，因为您的输入是一个

import re

pattern = re.compile(r'^\d{4}\-(0?[1-9]|1[012])\-(0?[1-9]|[12][0-9]|3[01])
输出的字符串：
First is valid date
Second is invalid
Third is invalid

  REGEX说明：

 ^ and $将字符串
\ d {4}的启动和结尾用于允许4位数字
（0？[[[[] 1-9] | 1 [012]）将允许1或2位月份，范围从1/01到12
 （0？[1-9] | [12] [0-9] | 3 [01]）将搜索01至09、10至19或20至29和30或31

)
first = '2020-01-01'
second = '2020-01-01 01:24:37 UTC'
third = '2020-13-01'

if pattern.match(first):
    print('First is valid date')
else:
    print('First is invalid')

if pattern.match(second):
    print('Second is valid date')
else:
    print('Second is invalid')

if pattern.match(third):
    print('Third is valid date')
else:
    print('Third is invalid')

输出的字符串：

REGEX说明：

^ and $将字符串
\ d {4}的启动和结尾用于允许4位数字
（0？[[[[] 1-9] | 1 [012]）将允许1或2位月份，范围从1/01到12
（0？[1-9] | [12] [0-9] | 3 [01]）将搜索01至09、10至19或20至29和30或31

You could use regex for that purpose, since your input is a string

import re

pattern = re.compile(r'^\d{4}\-(0?[1-9]|1[012])\-(0?[1-9]|[12][0-9]|3[01])
Which outputs:
First is valid date
Second is invalid
Third is invalid

Regex explanation:

^ and $ to delimiter start and end of string
\d{4} to allow 4 digits
(0?[1-9]|1[012]) will allow 1 or 2 digit month ranging from 1/01 to 12
(0?[1-9]|[12][0-9]|3[01]) will search for 01 to 09, 10 to 19 or 20 to 29, and 30 or 31

)
first = '2020-01-01'
second = '2020-01-01 01:24:37 UTC'
third = '2020-13-01'

if pattern.match(first):
    print('First is valid date')
else:
    print('First is invalid')

if pattern.match(second):
    print('Second is valid date')
else:
    print('Second is invalid')

if pattern.match(third):
    print('Third is valid date')
else:
    print('Third is invalid')

Which outputs:

Regex explanation:

^ and $ to delimiter start and end of string
\d{4} to allow 4 digits
(0?[1-9]|1[012]) will allow 1 or 2 digit month ranging from 1/01 to 12
(0?[1-9]|[12][0-9]|3[01]) will search for 01 to 09, 10 to 19 or 20 to 29, and 30 or 31

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