有没有办法在列表中进行随机数，我可以决定应该有多少个数字C＃

Question

我正在尝试获取带有随机数字的列表，

当我启动应用程序时，我要决定要插入哪个数字，但插入件什么都不做，我知道缺少编码数字的东西生成器，但我只是找不到它是什么。

因此，基本上我希望它显示此信息，如果我键入5个

随机数

随机数随机数

随机数

随机数

随机数

，那么如果我键入3，我希望它向我展示其中有多少个。

现在我制作了此代码：

Console.Write("insert number to decide: ");
int numbers = Convert.ToInt32(Console.ReadLine());
Console.Write("Number to count: ");
int yoy = Convert.ToInt32(Console.ReadLine());

Random random = new Random();

numbers = random.Next(0, 10);


var number = numbers;

var count = 0;
var digit = yoy;

var n = number;
while (n > 0)
{
    if (n % 10 == digit)
        count++;
    n = n / 10;
}

Console.WriteLine($"Number: {number}");
Console.WriteLine(
    $"Digit {digit} appears {count} times.");

Console.ReadKey();

Answer 1

让我尝试解释您的代码

Console.Write("insert number to decide: ");
int numbers = Convert.ToInt32(Console.ReadLine());
Console.Write("Number to count: ");
int yoy = Convert.ToInt32(Console.ReadLine());

Random random = new Random();

numbers = random.Next(0, 10); // You are overwriting user input here from line 2.


var number = numbers; // Redundant duplicate variable.

var count = 0;
var digit = yoy;

var n = number;
while (n > 0)
{
    if (n % 10 == digit)
        count++;
    n = n / 10;
}

Console.WriteLine($"Number: {number}");
Console.WriteLine(
    $"Digit {digit} appears {count} times.");

Console.ReadKey();

您要实现什么？
如果要计算一个数字在0和用户输入之间的随机数中的出现，则我将在第6行中写下此：

numbers = random.Next(0, numbers + 1);

如果不包括用户输入，请删除'+ 1'。

更新：

对于您的更新说明，我将写：

Console.Write("insert number to decide: ");
string userNumber = Console.ReadLine();
Console.Write("Number to count: ");
string userYoy = Console.ReadLine();

int number = 0;
int yoy = 0;
int count = 0;

bool numbersSuccess = int.TryParse(userNumber, out number);
bool yoySuccess = int.TryParse(userYoy, out yoy);

if(numberSuccess && yoySuccess)
{
    Random random = new Random();
    List<int> numbers = new List<int>();
   
    for(int i = 0; 0 < number; i++)
    {
        int randomNumber = random.Next(0,10);
        if(randomNumber == yoy)
        {
            count++;
        }
        Console.WriteLine($"Number: {randomNumber}");

    }
    Console.WriteLine(
    $"Digit {yoy} appears {count} times.");
}
else
{
    Console.WriteLine("Something went wrong, only type hole numbers!");
}
Console.ReadKey();

n DIGIT长度随机数的更新＃2

，您可以写下类似的内容：

Console.Write("insert number to decide: ");
string userNumber = Console.ReadLine();
Console.Write("Number to count: ");
string userYoy = Console.ReadLine();

int numberOfDigits = 0;
int yoy = 0;
int count = 0;

bool numbersSuccess = int.TryParse(userNumber, out numberOfDigits );
bool yoySuccess = int.TryParse(userYoy, out yoy);

if(numberSuccess && yoySuccess)
{
    int randomMax = (int)Math.Pow(10,numberOfDigits);

    Random random = new Random();
    int number = random.Next(0,randomMax);

    var n = number;
    while (n > 0)
    {
        if (n % 10 == digit)
            count++;
        n = n / 10;
    }

    Console.WriteLine($"Number: {number}");
    Console.WriteLine($"Digit {digit} appears {count} times.");
}
else
{
    Console.WriteLine("Something went wrong, only type hole numbers!");
}
Console.ReadKey();