如何泡泡排序存储一个集体字段的数组？

Question

    void Bubblesort(City []cities, int num)
    {
        
        for(int i = 0; i < num - 1; i++)
        {
            for (int j = 0; j < num - 1 - i; j++)
            {
                if (cities[j].CityTemperature < cities[j].CityTemperature + 1)
                {
                    var tempvariable = cities[j];
                    cities[j] = cities[j + 1];
                    cities[j + 1] = tempvariable;
                }
            }
        }   
        for (int i = 0; i < num; i++)
        {
            Console.WriteLine(cities[i].ToString()); 
            
        }
    }   
    static void Main(string[] args)
    {
        Console.WriteLine("welcome to enter the name of the city and its temperature between -60 and 60 Celsius \n you will have to enter 4 elements of each :-) \n\n\n\n");
        City[] cities = new City[4];
        Program myProgram = new Program();
        var num = cities.Length;

        for (int i = 0; i < cities.Length; i++)
        {
            cities[i] = new City();
            Console.Write("Name of City ?: ");
            cities[i].CityName = Console.ReadLine();
            Console.Write("what Temp ?: ");
            cities[i].CityTemperature = System.Convert.ToInt32(System.Console.ReadLine());
            Console.Clear();
        }

        myProgram.Bubblesort(cities, num);

        Console.WriteLine("press a button of choice and hit enter to close the program, \n Byebye :-)");
        Console.ReadKey();
    }
}

///我的城市班级

私人字符串名称； 私有int温度；

    public string CityName
    {
        get { return name; }
        set { name = value; }
    }
    public int CityTemperature
    {
        get { return temperature; }
        set { temperature = value; }
    }
    public override string ToString()
    {
        
        return "City: " + CityName + " City temperature: " + CityTemperature;
    }

因此，基本上用户输入城市名称和城市 温度存储到类的场中， 我想通过温度将阵列泡泡，这样它将 使输出从最冷到最温暖的分类。 你能看到从哪里开始吗？我一直在想 弄清楚我在调用函数时是否经过错误的参数 并一直在尝试通过循环和实验来改变。
我想也许我不比较温度值 而且它做了其他事情。但是，分类永远不会发生。 感谢您花的时间来看看这个。*