在字典和Nested Array＆amp;中查找匹配键将数组替换为中的值
我也有一个类似的问题，例如 ;用价值替换键
但是我的情况看起来像这样。
d1 = {"1": "DNS Compromise", "2": "DNS Poisoning", "3": "Fraud Orders"}
d2 = {... ,"categories": [1, 2], ...}
我想拥有以下输出：
d2 = {..., "categories": [DNS Compromise, DNS Poisoning], ...}
有没有办法构造循环或使用理解？我是新手。
I have sort of a similar question as Find matching keys in dictionaries & replace keys with values
However my situation looks like this.
d1 = {"1": "DNS Compromise", "2": "DNS Poisoning", "3": "Fraud Orders"}
d2 = {... ,"categories": [1, 2], ...}
I would like to have the following output:
d2 = {..., "categories": [DNS Compromise, DNS Poisoning], ...}
Is there a way to construct a for loop or use comprehension? I am sort of new to this.
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使用字典，您可以轻松获取使用方法
values（）的值列表。With dictionary you can easily get a list of the values with the method
values().这是您要搜索的解决方案：
d3 = {k：[d1 [str（v_i）] for v_i in V in V in v] for d2.items（）}}in v in v in V in v]This is the solution you are searching for :
d3 = {k:[ d1[str(v_i)] for v_i in v] for k,v in d2.items() }