在搜索字符串时，如何从列表列表中返回列表，并强制将比较与小写列表？

发布于 2025-01-29 13:00:56 字数 518 浏览 2 评论 0原文

我有这样的列表：

allTeams = [ [57, 'Arsenal FC', 'Arsenal', 'ARS'], [58, 'Aston Villa FC', 'Aston Villa', 'AVL'], [61, 'Chelsea FC', 'Chelsea', 'CHE'], ...]

userIsLookingFor = "chelsea"
    
for team in allTeams:
    if userIsLookingFor.lower() in any_element_of_team.lower():
        print(team)
  

> [61, 'Chelsea FC', 'Chelsea', 'CHE']

我基本上会在列表列表中查找用户的请求单词，如果有匹配项，我会打印该列表。在上面的情况下，用户搜索“切尔西”，在其中一个列表中，“切尔西”（切尔西FC或切尔西都没有关系）。因此，我将返回该特定列表。

我尝试使用“任何”，但它似乎只返回布尔值，而我实际上无法从中打印任何列表。

原文

I have a list of lists as such:

allTeams = [ [57, 'Arsenal FC', 'Arsenal', 'ARS'], [58, 'Aston Villa FC', 'Aston Villa', 'AVL'], [61, 'Chelsea FC', 'Chelsea', 'CHE'], ...]

userIsLookingFor = "chelsea"
    
for team in allTeams:
    if userIsLookingFor.lower() in any_element_of_team.lower():
        print(team)
  

> [61, 'Chelsea FC', 'Chelsea', 'CHE']

I would basically look for the user's requested word in a list of lists, and if there's a match, I print that list. In the case above, the user searches for "chelsea" and in one of the lists, there's a match for "chelsea" (either Chelsea FC or Chelsea, doesn't matter). So I would return that specific list.

I tried using "any" but it seems to only return a boolean and I can't actually print any list from it.

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腻橙味 2025-02-05 13:00:56

您可以使用列表理解：

userIsLookingFor = "chelsea"

# option 1, exact match item 2
[l for l in allTeams if l[2].lower() == userIsLookingFor]


# option 2, match on any word
[l for l in allTeams
 if any(x.lower() == userIsLookingFor
        for s in l if isinstance(s, str)
        for x in s.split())
]

输出：

[[61, 'Chelsea FC', 'Chelsea', 'CHE']]

You can use a list comprehension:

userIsLookingFor = "chelsea"

# option 1, exact match item 2
[l for l in allTeams if l[2].lower() == userIsLookingFor]


# option 2, match on any word
[l for l in allTeams
 if any(x.lower() == userIsLookingFor
        for s in l if isinstance(s, str)
        for x in s.split())
]

output: