如何从discord.py中获取reddit的client_id，client_secret和user_agent参数

发布于 2025-01-29 04:25:17 字数 741 浏览 3 评论 0原文

我正在创建一个discord.py bot，我想做的就是添加！meme命令，从r/memes subreddit中汲取随机模因。关于如何做到这一点，我在堆栈溢出上找到了一些代码。我的问题是我需要3个参数，client_id，client_secret和user_agent，我不知道该如何获取。这是我发现的代码：

reddit = praw.Reddit(client_id='CLIENT_ID HERE',
                     client_secret='CLIENT_SECRET HERE',
                     user_agent='USER_AGENT HERE')

@bot.command()
async def meme():
    memes_submissions = reddit.subreddit('memes').hot()
    post_to_pick = random.randint(1, 10)
    for i in range(0, post_to_pick):
        submission = next(x for x in memes_submissions if not x.stickied)

    await bot.say(submission.url)

有人可以帮助我获得这些参数吗？

原文

I'm creating a Discord.py bot and what I want it to do is add a !meme command on which it pulls a random meme from the r/memes subreddit. I have found some code on Stack Overflow as to how to do that. My problem is that I need 3 parameters, client_id, client_secret and user_agent, which I don't know how to get. Here's the code I found:

reddit = praw.Reddit(client_id='CLIENT_ID HERE',
                     client_secret='CLIENT_SECRET HERE',
                     user_agent='USER_AGENT HERE')

@bot.command()
async def meme():
    memes_submissions = reddit.subreddit('memes').hot()
    post_to_pick = random.randint(1, 10)
    for i in range(0, post_to_pick):
        submission = next(x for x in memes_submissions if not x.stickied)

    await bot.say(submission.url)

Can someone help me get those parameters?

分享到QQ

分享到微博