尝试将.ASCIIZ字符串复制到MIPS中的分配空间

发布于 2025-01-29 02:13:53 字数 393 浏览 1 评论 0原文

我试图制作一个简单的程序，将字符串soplas复制到.Space指令称为buffer。我会遇到错误，但我不确定我在哪里出错，beq语句将将字节与0 ASCII字符进行比较，因为那是如何终止字符串，对吗？使用JAL调用复制

copy:   
     lb   $t1, soplas($t0) 
     nop
     sb   $t1, buffer($t0)
     nop
     addi $t0, $t0,1
     beq  $t1, 0x00, done
     j copy
     nop
     nop
    
    
done: 
    jr $ra
    nop
    nop

原文

im trying to make a simple program that copies a string soplas to a .space directive called buffer. im getting errors but im not sure where im going wrong, the beq statement would be comparing the byte to the 0 ascii character since thats how strings are null terminated, right? copy is called using jal, hence the jr $ra in the done subroutine

copy:   
     lb   $t1, soplas($t0) 
     nop
     sb   $t1, buffer($t0)
     nop
     addi $t0, $t0,1
     beq  $t1, 0x00, done
     j copy
     nop
     nop
    
    
done: 
    jr $ra
    nop
    nop

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烟火散人牵绊 2025-02-05 02:13:53

假设您的C代码看起来像这样：

void copy() {
    int i = 0; // start i at 0 to work with soplas[0]/buffer[0]
    while (true) {
        char ch = soplas[i];
        buffer[i] = ch;
        i++;
        if (ch == '\0') break;
    }
}

您可以看到汇编版本中缺少的C代码的哪一行？

另外，如果您使用带有分支延迟插槽的MIPS，即使BEQ和bne需要nop s，而不仅仅是j j 代码>和JR。

Let's say your C code would look like this:

void copy() {
    int i = 0; // start i at 0 to work with soplas[0]/buffer[0]
    while (true) {
        char ch = soplas[i];
        buffer[i] = ch;
        i++;
        if (ch == '\0') break;
    }
}

Can you see which line of the C code you're missing in the assembly version?

Also, if you're using MIPS with branch delay slots, even beq and bne need nops, not just j and jr.

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