检查空手道中是否存在请求标头
我正在尝试创建一个模拟服务器，以处理空手道的功能测试。为此，我需要根据某些元素（例如在传入请求中的方法，路径和“授权”标头的存在）匹配某些传入请求。
我拥有的条件类似：
methodIs('get') && pathMatches('/mypath')
我需要为请求中存在“授权”标头编写条件。
根据文档，我们可以使用：
karate.get('requestHeaders.Authorization[0]') == 'foo'
但是，当我尝试使用上述内容时，它不起作用。我检查了requestheaders.authorization [0]的存在，但这被返回为null。我的想法是将上述内容修改为karate.get（'requestheaders.authorization [0]'）=='#notnull'。
我最终尝试了headerContains（'授权'，''），它似乎在起作用 - 但是我不确定这是否是检查该特定标头的存在的正确方法。还有其他（更好的）方法吗？
I am trying to create a mock server for handling functional tests in Karate. For that purpose I need to match certain incoming requests based on certain elements like method, path and presence of "Authorization" header in the incoming requests.
The condition I have is something like:
methodIs('get') && pathMatches('/mypath')
I need to write a condition for the presence of an "Authorization" header in the request.
As per documentation, we can use:
karate.get('requestHeaders.Authorization[0]') == 'foo'
However, when I am trying to use the above, it isn't working. I checked for the presence of requestHeaders.Authorization[0] but that is being returned as Null. My idea was to modify the above to something like karate.get('requestHeaders.Authorization[0]') == '#notnull'.
I ended up trying headerContains('Authorization',''), which seems to be working - however I am not sure if that is the right way to check for the presence of that specific header. Is there any other (better) way to do this?
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我们计划在以后的发行版中改善这一点： https：//githbithub.com/karatelabs/karatelabs/karate/karate/karate/karate/karate/karate/karate/karate/karate/karate- /essugy/1962
同时，我本来想到一个简单的javaScript条件，例如
requestheaders.uthorization将起作用。例如：不幸的是，这是对病例敏感的，这是我们计划在以后的版本中修复的方法。您可以暂时使用或条件。
有关更多说明，请参阅： https://stackoverflow.com/a/555823180/143475
We are planning to improve this in a future release: https://github.com/karatelabs/karate/issues/1962
Meanwhile I would have thought that a simple JavaScript condition like
requestHeaders.Authorizationwould work. For e.g:Unfortunately it is case-sensitive, which is what we plan to fix in a future release. You could use an OR condition for the time being.
For more explanation, refer: https://stackoverflow.com/a/55823180/143475