如何打印列表的所有独特组合？

发布于 2025-01-28 23:59:21 字数 163 浏览 1 评论 0原文

list_a = [1, 2, 3]

我想打印列表中的所有唯一组合，如此

[ [1], [2], [3], [1, 2], [1, 3], [2, 3], [1, 2, 3] ]

注：不使用任何模块

原文

list_a = [1, 2, 3]

I want to print all the unique combinations from the list like this

[ [1], [2], [3], [1, 2], [1, 3], [2, 3], [1, 2, 3] ]

Note: Without using any module

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眼趣 2025-02-04 23:59:21

您需要 powerset refipe =“ https://docs.python.org/3/library/itertools.html” rel =“ nofollow noreferrer”> itertools

from itertools import combinations, chain
def powerset(iterable):
    "powerset([1,2,3]) --> () (1,) (2,) (3,) (1,2) (1,3) (2,3) (1,2,3)"
    s = list(iterable)
    return chain.from_iterable(combinations(s, r) for r in range(1, len(s)+1))

list_a = [1, 2, 3]

out = list(map(list, powerset(list_a)))

output：[[1]，，，，，，，，，，，地[2]，[3]，[1，2]，[1，3]，[2，3]，[1，2，3]]

如果您不想使用itertools使用列表综合或功能，您可以很容易地轻松地重新进来组合链条。

You need a variant of the powerset recipe from itertools:

from itertools import combinations, chain
def powerset(iterable):
    "powerset([1,2,3]) --> () (1,) (2,) (3,) (1,2) (1,3) (2,3) (1,2,3)"
    s = list(iterable)
    return chain.from_iterable(combinations(s, r) for r in range(1, len(s)+1))

list_a = [1, 2, 3]

out = list(map(list, powerset(list_a)))

output: [[1], [2], [3], [1, 2], [1, 3], [2, 3], [1, 2, 3]]

If you don't want to use itertools you can quite easily reimplement combinations and chain using list comprehensions or functions.

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