可以在Kotlin上显示/隐藏菜单项 - Android Studio
我的应用程序包含3个选项的菜单,我想要的是,根据我定义的条件,仅显示2个选项,或显示3个选项。 我尝试了我在Google和这里找到的所有选项,但是没有一个对我有用的选择。
我的想法是,一旦创建了视图,菜单就已经显示了可以根据条件显示的选项。但是,由于我能够实现它,因此我添加了一个按钮来模拟事件。
非常感谢您的帮助。
在这里我附加代码:
1)activity_home.xml(某些部分)
<Button
android:id="@+id/button"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Button"
android:onClick="ActivarMenus"/>
<androidx.appcompat.widget.Toolbar
android:id="@+id/toolbar"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:background="?attr/colorPrimary"
android:minHeight="?attr/actionBarSize"
app:menu="@menu/home_menu"
app:layout_constraintEnd_toEndOf="parent"
app:layout_constraintStart_toStartOf="parent"
app:layout_constraintTop_toTopOf="parent" >
2)aqui el Archivo home_menu.xml
<?xml version="1.0" encoding="utf-8"?>
<menu xmlns:tools="http://schemas.android.com/tools"
xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto">
<item
android:id="@+id/menu_item"
android:icon="@drawable/ic_baseline_more_vert_24"
app:showAsAction="ifRoom"
tools:ignore="MenuTitle">
<menu>
<item
android:id="@+id/newRegister"
android:icon="@drawable/ic_baseline_add_24"
app:showAsAction="always"
android:visible="true"
android:title="Nueva Orden Swab" />
<item
android:id="@+id/newAnexoo"
android:icon="@drawable/ic_baseline_add_24"
app:showAsAction="always"
android:visible="true"
android:title="Nuevo Formulario Anexo O" />
<item
android:id="@+id/sync"
android:icon="@drawable/ic_baseline_sync_24"
app:showAsAction="always"
android:visible="true"
android:title="Sincronizar" />
</menu>
</item>
</menu>
3)和一部分homeactivity.kt
class HomeActivity : ActivityViewBinding<ActivityHomeBinding, HomeVM>() {
private var mainMenu: Menu? = null
private lateinit var spm : SharedPreferencesManager
private val adapter: OrderAdapter by inject()
override fun inflateLayout(layoutInflater: LayoutInflater) =
ActivityHomeBinding.inflate(layoutInflater)
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.activity_home)
//MenuMain.findItem(R.id.newAnexoo).isVisible = true
}
override fun onCreateOptionsMenu(menu: Menu): Boolean {
val inflater: MenuInflater = menuInflater
inflater.inflate(R.menu.home_menu, menu)
mainMenu = menu;
return true
}
fun ActivarMenus(view: View) {
mainMenu?.findItem(R.id.newRegister)?.isVisible = true
}
my application has a menu of 3 options, and what I want is that according to a condition that I define, it shows only 2 options, or it shows 3.
I have tried all the options that I have found on google and here, but none have worked for me.
My idea is that as soon as the view is created, the menu already shows the options that it can show according to the condition. But as I have been able to achieve it, I added a button to simulate the event.
I would greatly appreciate your help.
Here I attach the code:
1) activity_home.xml (some part)
<Button
android:id="@+id/button"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Button"
android:onClick="ActivarMenus"/>
<androidx.appcompat.widget.Toolbar
android:id="@+id/toolbar"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:background="?attr/colorPrimary"
android:minHeight="?attr/actionBarSize"
app:menu="@menu/home_menu"
app:layout_constraintEnd_toEndOf="parent"
app:layout_constraintStart_toStartOf="parent"
app:layout_constraintTop_toTopOf="parent" >
2) Aqui el archivo home_menu.xml
<?xml version="1.0" encoding="utf-8"?>
<menu xmlns:tools="http://schemas.android.com/tools"
xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto">
<item
android:id="@+id/menu_item"
android:icon="@drawable/ic_baseline_more_vert_24"
app:showAsAction="ifRoom"
tools:ignore="MenuTitle">
<menu>
<item
android:id="@+id/newRegister"
android:icon="@drawable/ic_baseline_add_24"
app:showAsAction="always"
android:visible="true"
android:title="Nueva Orden Swab" />
<item
android:id="@+id/newAnexoo"
android:icon="@drawable/ic_baseline_add_24"
app:showAsAction="always"
android:visible="true"
android:title="Nuevo Formulario Anexo O" />
<item
android:id="@+id/sync"
android:icon="@drawable/ic_baseline_sync_24"
app:showAsAction="always"
android:visible="true"
android:title="Sincronizar" />
</menu>
</item>
</menu>
3) And a part of the HomeActivity.kt
class HomeActivity : ActivityViewBinding<ActivityHomeBinding, HomeVM>() {
private var mainMenu: Menu? = null
private lateinit var spm : SharedPreferencesManager
private val adapter: OrderAdapter by inject()
override fun inflateLayout(layoutInflater: LayoutInflater) =
ActivityHomeBinding.inflate(layoutInflater)
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.activity_home)
//MenuMain.findItem(R.id.newAnexoo).isVisible = true
}
override fun onCreateOptionsMenu(menu: Menu): Boolean {
val inflater: MenuInflater = menuInflater
inflater.inflate(R.menu.home_menu, menu)
mainMenu = menu;
return true
}
fun ActivarMenus(view: View) {
mainMenu?.findItem(R.id.newRegister)?.isVisible = true
}
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您应该尝试使用此操作。
如果要在运行时更改菜单项,则可以使用
onprepareoptionsmenu
You should try this one it might be work.
if you want to change Menu Items at Run time You can use
onPrepareOptionsMenu