基于C＆＃x2B;＆＃x2B;初始化数组版本和编译器
In C++11 or higher regardless of compiler int myArray[10] = { 0 }; would initialize to all elements to zero.问题是，这也可以在C ++ 98中起作用，并且编译器是否可以决定将所有元素初始化为零？换句话说，用给定编译器的C ++ 98可以忽略所有元素的零分配吗？
我找到了此页面： https://en.cppreferent /Zero_Initialization 列出了C ++ 98关于零初始化的缺陷。
In C++11 or higher regardless of compiler int myArray[10] = { 0 }; would initialize to all elements to zero. The question is would this also work in C++98 and could the compiler not decide to initialize all elements to zero? In other words could C++98 with a given compiler ignore the assigning zero to all elements?
I found this page: https://en.cppreference.com/w/cpp/language/zero_initialization which lists C++98 defects about zero initialization.
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所有元素均为零。 C ++的引号98：
与从C ++ 03开始的含义相比，默认初始化的含义在C ++ 98中截然不同，在C ++ 03中，旧的默认初始化本质上是重新命名的值初始化，而新的默认初始化变成了“无初始化”的意思。
请注意，
int myarray [10] = {};将实现相同的目标。不必明确地为第一个元素提供值。All elements would be zero. Quotes from C++98:
The meaning of default initialisation was radically different in C++98 compared to its meaning starting from C++03 where the old default initialisation essentially was renamed value initialisation and the new default initialisation became to mean "no initialisation" for trivial types.
Note that
int myArray[10] = {};would achieve the same goal. It's unnecessary to explicitly provide a value for the first element.