如何将INT32_T的4个字节写入C中的Big-Endian订单的二进制文件？
我想将int32_t的4个字节写入大端顺序的二进制文件。我直接使用了fwrite（）和指向我的int32_t的指针，但它有些可行，但问题是我的整数是用小序列编写的，字节先写。例如，如果我写的话：
int32_t specialInt = 262;
fwrite(&specialInt, 4, 1, myFile);
我会用十六进制编辑器打开它，我会看到：
06 01 00 00 ...
与我想要的方式相比，这是倒退的。我想要：
00 00 01 06 ...
如何使我的int_32t按大阶订单？是否有一个内置的C库函数可以以正确的顺序获取字节，或者我应该使用memcpy（）将字节放入温度char阵列中，然后一一写入字节向后倒入文件？
I want to write the 4 bytes of an int32_t to a binary file in big-endian order. I used fwrite() directly with a pointer to my int32_t, and it somewhat works, but the problem is that my integer is written in little-endian order, with the smallest bytes written first. For example, if I write:
int32_t specialInt = 262;
fwrite(&specialInt, 4, 1, myFile);
and I open it with my hex editor, I see:
06 01 00 00 ...
which is backwards compared to how I want it. I would like:
00 00 01 06 ...
How should I get my int_32t to be in big-endian order? Is there a built-in C library function that will get the bytes in the correct order, or should I use memcpy() to put the bytes into a temp char array, then write the bytes one by one backwards into the file?
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感谢PMG在评论中写下答案：
假设
char_bit == 8：Thanks pmg for writing the answer in the comment:
Assuming
CHAR_BIT == 8:您可以在POSIX 2001标准中使用
htonl（）函数arpa/inet.h标题。参见 https://linux.die.net/man/3/ntohl是互联网字节订单，称为“网络字节订单”。
您需要将
int32_t转换为uint32_t。该铸件由C标准定义。接下来，它通过htonl（）将其转换为网络endian，然后将其写入文件：可以用复合文字来缩写一点。
You could use
htonl()function from POSIX 2001 standard available inarpa/inet.hheader. See https://linux.die.net/man/3/ntohlBig endian is Internet byte order, known as "network byte order".
You need to transform
int32_ttouint32_t. This cast is defined by C standard. Next transform it to network endian viahtonl()and then write it to a file:It could be abbreviated a bit with a compound literal.