我如何用pygame墙？

Question

我试图通过与朋友制作简单的Pacman游戏来学习Pygame的基础知识，但是我一直在弄清楚如何制作墙壁并与Pacman和The Wall碰撞，并在墙壁上停止运动。 （这是2个玩家的pacman，鬼是箭头键，而Pacman是wasd）

这是Main.py

import pygame
import random
import time
from Pacman import pacman
from Ghost import ghost

#colors
Yellow = (255,255,0)
Blackish_Blue = (20,0,70)
Red = (255,0,0)
P_B = (40,60,100)



clock = pygame.time.Clock()



#display
pygame.init()
pygame.display.set_caption('  Scuffed Pacman')
width, height = 640, 480
screen = pygame.display.set_mode((width, height))

pacman = pacman(screen)
ghost = ghost(screen)


font = pygame.font.Font('freesansbold.ttf', 32)
text = font.render('Game Over', True, Yellow)
textRect = text.get_rect()
textRect.center = (width / 2, height / 2)

run = True
while run == True:
  pygame.time.delay(10)
  clock.tick(60)
  screen.fill(Blackish_Blue)

  for event in pygame.event.get():
    if event.type == pygame.QUIT:
      run = False

  

  
  
  
  color = (182,163,192)
  #attempt to make wall and check collision
  ghostspawn = pygame.Rect(0,0,60,40)
  ghostspawn.center = (width / 2, (height / 2)-50)
  pygame.draw.rect(screen, color, ghostspawn)
  if ghostspawn.collidepoint(pacman.x, pacman.y):
    print("collision detected")
  
  
  pacman.draw(screen)
  ghost.draw(screen)
  ghost.update()
  pacman.update()


  distance = (((pacman.x - ghost.x)**2) + ((pacman.y - ghost.y)**2))**(1/2)
  sumrad = pacman.radius + ghost.radius

  if distance < sumrad:
    while True:
      screen.fill(P_B)
      screen.blit(text, textRect)
      for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            quit()
        pygame.display.update()
  
  pygame.display.update()

pygame.quit()

这是Pacman的代码：

import pygame

Yellow = (255,255,0)
class pacman(pygame.sprite.Sprite):
  def __init__(self, mainscreen):
    super().__init__()
    self.x = 320
    self.y = 240
    self.radius = 15
    self.velocity = 2
    self.origin = (self.x, self.y)
  
  def draw(self, mainscreen):
    pygame.draw.circle(mainscreen, Yellow, (self.x, self.y), self.radius)
  
  
  def update(self):
    self.movement()
    self.origin = (self.x, self.y)
    
  def movement(self):
    keys = pygame.key.get_pressed()

    if keys[pygame.K_d] and self.velocity > 0 and self.x < 625:
        self.x += self.velocity
    if keys[pygame.K_a] and self.velocity > 0 and self.x > 15:
      self.x -= self.velocity
    if keys[pygame.K_w] and self.velocity > 0 and self.y > 15:
      self.y -= self.velocity
    if keys[pygame.K_s] and self.velocity > 0 and self.y < 465:
      self.y += self.velocity

这是Ghost的代码：

import pygame
Red = (255,0,0)
class ghost(pygame.sprite.Sprite):
  def __init__(self, mainscreen):
    super().__init__()
    self.x = 213
    self.y = 240
    self.radius = 15
    self.velocity = 2
    self.origin = (self.x, self.y)
  
  def draw(self, mainscreen):
    pygame.draw.circle(mainscreen, Red, (self.x, self.y), self.radius)
  
  
  def update(self):
    self.movement()
    self.origin = (self.x, self.y)
    
  def movement(self):
    keys = pygame.key.get_pressed()
    if keys[pygame.K_RIGHT] and self.velocity > 0 and self.x < 625:
      self.x += self.velocity
    if keys[pygame.K_LEFT] and self.velocity > 0 and self.x > 15:
      self.x -= self.velocity
    if keys[pygame.K_UP] and self.velocity > 0 and self.y > 15:
      self.y -= self.velocity
    if keys[pygame.K_DOWN] and self.velocity > 0 and self.y < 465:
      self.y += self.velocity

这是我检查Wall Collision的尝试，但我我不知道如何阻止Pacman和幽灵经历。碰撞还仅检查圆的中间。

ghostspawn = pygame.Rect(0,0,60,40)
ghostspawn.center = (width / 2, (height / 2)-50)
pygame.draw.rect(screen, color, ghostspawn)
if ghostspawn.collidepoint(pacman.x, pacman.y):
  print("allowed")

这是我发现Pacman和Ghost之间的碰撞的方式，因为它可能对墙壁进行有帮助，但我不知道如何进行。

distance = (((pacman.x - ghost.x)**2) + ((pacman.y - ghost.y)**2))**(1/2)
sumrad = pacman.radius + ghost.radius

我在这里看了一些类似的问题，但我无法完全掌握它的工作原理。 因此，如果有人能提供帮助，我在检查圆圈和矩形之间的碰撞方面遇到了麻烦，并且还可以防止圆圈/Pacman穿过。

Answer 1

要检查一个圆圈是否与墙壁碰撞，您只需要做2件事，

以获取圆圈和墙之间的距离

，然后检查距离是否较小还是等于圆的距离

：

distance = abs(circle.x - wall.x) + abs(circle.y - wall.y)
if distance <= circle.radius: # abs() Makes the value in the brackets positive
    circle.x = oldX
    circle.y = oldY

要用您的距离游戏将首先在self。self .__ Int __（）中添加self.oldx和self.oldy在Pacman和Ghost类中。我现在将它们设置为0。

然后，我将在移动对象之前更新移动功能中的oldx和Oldy，

def movement(self):
    keys = pygame.key.get_pressed()
    self.oldX = self.x
    self.oldY = self.y

    if keys[pygame.K_d] and self.velocity > 0 and self.x < 625:
        self.x += self.velocity
    if keys[pygame.K_a] and self.velocity > 0 and self.x > 15:
        self.x -= self.velocity
    if keys[pygame.K_w] and self.velocity > 0 and self.y > 15:
        self.y -= self.velocity
    if keys[pygame.K_s] and self.velocity > 0 and self.y < 465:
        self.y += self.velocity

然后我将拥有一个包含游戏中的每堵墙的列表，以及一个包含游戏中每个幽灵的列表（也就是您想有多个幽灵）。

然后，我将进入主循环（您拥有的while循环），然后在调用鬼魂的运动功能和pacman 之后，我会添加此：

for wall in walls:
    distance = abs(pacman.x - wall.x) + abs(pacman.y - wall.y)
       if distance <= pacman.radius:
           pacman.x = pacman.oldX
           pacman.y = pacman.oldY

    for ghost in ghosts:
        distance = abs(ghost.x - wall.x) + abs(ghost.y - wall.y)
           if distance <= ghost.radius:
               ghost.x = ghost.oldX
               ghost.y = ghost.oldY

这应该有效，谢谢。