如何从Python中的发电机表达式打印Unicode？
创建来自Generator表达式的列表：
V = [('\\u26' + str(x)) for x in range(63,70)]
第一个问题：如果您尝试仅使用“ \ u” + str（...），它立即给出解码器错误。似乎它在看到\ u时，而不是在准备好时，它试图立即解码。我试图通过双重斜击来解决这个问题。
其次，这创造了一些有希望的东西，但仍然无法实际将它们打印为Unicode的控制器：
>>> print([v[0:] for v in V])
['\\u2663', '\\u2664', '\\u2665', .....]
>>> print(V[0])
\u2663
我希望看到的是与使用'\ u0123'之类的命令相同的符号列表，例如：
>>> print('\u2663')
♣
有什么方法可以从生成的列表中做到这一点？还是有更好的方法可以打印它们而不是'\ u0123'格式？
这不是我想要的。我想查看绘制的实际符号，而不是Unicode值：
>>> print(['{}'.format(v[0:]) for v in V])
['\\u2663', '\\u2664', '\\u2665', '\\u2666', '\\u2667', '\\u2668', '\\u2669']
Create a list from generator expression:
V = [('\\u26' + str(x)) for x in range(63,70)]
First issue: if you try to use just "\u" + str(...) it gives a decoder error right away. Seems like it tries to decode immediately upon seeing the \u instead of when a full chunk is ready. I am trying to work around that with double backslash.
Second, that creates something promising but still cannot actually print them as unicode to console:
>>> print([v[0:] for v in V])
['\\u2663', '\\u2664', '\\u2665', .....]
>>> print(V[0])
\u2663
What I would expect to see is a list of symbols that look identical to when using commands like '\u0123' such as:
>>> print('\u2663')
♣
Any way to do that from a generated list? Or is there a better way to print them instead of the '\u0123' format?
This is NOT what I want. I want to see the actual symbols drawn, not the Unicode values:
>>> print(['{}'.format(v[0:]) for v in V])
['\\u2663', '\\u2664', '\\u2665', '\\u2666', '\\u2667', '\\u2668', '\\u2669']
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Unicode是字节编码的字符，而不是逃脱序列。 python 3字符串是Unicode。要返回与Unicode代码点相对应的字符使用 noreflow noreferrer“> chr ：
要生成2663至2670之间的字符：
逃脱序列使用十六进制符号。 0x2663是小数为9827，而0x2670变为9840。
您也可以使用HEX数字文字：
的问题完全相同的逻辑
或者，使用与原始代码不起作用 ，是用来代表单个逃生序列的问题当我们不能或不想键入字符本身时，字符串中的字符。解释器或编译器用相应的角色即时替代它们。字符串
\\ u26是一个逃逸\，其次是u，2和66 ：：Unicode is a character to bytes encoding, not escape sequences. Python 3 strings are Unicode. To return the character that corresponds to a Unicode code point use chr :
To generate the characters between 2663 and 2670:
Escape sequences use hexadecimal notation though. 0x2663 is 9827 in decimal, and 0x2670 becomes 9840.
You can use also use hex numeric literals:
or, to use exactly the same logic as the question
The reason the original code doesn't work is that escape sequences are used to represent a single character in a string when we can't or don't want to type the character itself. The interpreter or compiler replaces them with the corresponding character immediatelly. The string
\\u26is an escaped\followed byu,2and6: