python版本3.10试图在图像中添加水印时会产生错误
注意:所有3.9版本都完美地运行代码,创建了水印图像。
我创建了这个项目,以适合一个完美适合图像大小的水印十字,但是在这条代码中:
paste_mask = watermark.split()[3].point(lambda i: i * TRANSPARENCY / 100.)
它生成此错误:
File "c:\Users\Computador\Desktop\Python\Watermark.py", line 29, in watermark_with_transparency
paste_mask = watermark.split()[3].point(lambda i: i * TRANSPARENCY / 100.)
File "C:\Users\Computador\AppData\Local\Programs\Python\Python310\lib\site-packages\PIL\Image.py", line 1723, in point
return self._new(self.im.point(lut, mode))
TypeError: 'float' object cannot be interpreted as an integer
完整的代码是:
from PIL import Image
def watermark_with_transparency(input_image_path,
output_image_path,
watermark_image_path):
TRANSPARENCY = 10
angle = 30
base_image = Image.open(input_image_path)
w_img, h_img = base_image.size
basewidth = w_img
watermark = Image.open(watermark_image_path)
watermark = watermark.rotate(angle, expand=True)
wpercent = (basewidth / float(watermark.size[0]))
hpercent = h_img / float(watermark.size[1])
if wpercent < hpercent:
hsize = int((float(watermark.size[1]) * float(wpercent)))
watermark = watermark.resize((basewidth, hsize), Image.ANTIALIAS)
else:
wsize = int((float(watermark.size[0]) * float(hpercent)))
watermark = watermark.resize((wsize, h_img), Image.ANTIALIAS)
w_logo, h_logo = watermark.size
center_y = int(h_img / 2)
center_x = int(w_img / 2)
top_y = center_y - int(h_logo / 2)
left_x = center_x - int(w_logo / 2)
if watermark.mode != 'RGBA':
alpha = Image.new('L', (w_img, h_img), 255)
watermark.putalpha(alpha)
paste_mask = watermark.split()[3].point(lambda i: i * TRANSPARENCY / 100.)
base_image.paste(watermark, (left_x, top_y), mask=paste_mask)
base_image.save(output_image_path)
图像中的模型还可以,我视图中的值正确,我应该修改如何在这个新的Python版本中使用?
Note: all 3.9 versions run the code perfectly creating the watermarked image.
I created this project to fit a watermark cross that perfectly fits the size of the image, but in this line of code:
paste_mask = watermark.split()[3].point(lambda i: i * TRANSPARENCY / 100.)
It generating this error:
File "c:\Users\Computador\Desktop\Python\Watermark.py", line 29, in watermark_with_transparency
paste_mask = watermark.split()[3].point(lambda i: i * TRANSPARENCY / 100.)
File "C:\Users\Computador\AppData\Local\Programs\Python\Python310\lib\site-packages\PIL\Image.py", line 1723, in point
return self._new(self.im.point(lut, mode))
TypeError: 'float' object cannot be interpreted as an integer
The complete code is:
from PIL import Image
def watermark_with_transparency(input_image_path,
output_image_path,
watermark_image_path):
TRANSPARENCY = 10
angle = 30
base_image = Image.open(input_image_path)
w_img, h_img = base_image.size
basewidth = w_img
watermark = Image.open(watermark_image_path)
watermark = watermark.rotate(angle, expand=True)
wpercent = (basewidth / float(watermark.size[0]))
hpercent = h_img / float(watermark.size[1])
if wpercent < hpercent:
hsize = int((float(watermark.size[1]) * float(wpercent)))
watermark = watermark.resize((basewidth, hsize), Image.ANTIALIAS)
else:
wsize = int((float(watermark.size[0]) * float(hpercent)))
watermark = watermark.resize((wsize, h_img), Image.ANTIALIAS)
w_logo, h_logo = watermark.size
center_y = int(h_img / 2)
center_x = int(w_img / 2)
top_y = center_y - int(h_logo / 2)
left_x = center_x - int(w_logo / 2)
if watermark.mode != 'RGBA':
alpha = Image.new('L', (w_img, h_img), 255)
watermark.putalpha(alpha)
paste_mask = watermark.split()[3].point(lambda i: i * TRANSPARENCY / 100.)
base_image.paste(watermark, (left_x, top_y), mask=paste_mask)
base_image.save(output_image_path)
The model in the image is ok and the values in my view are correct, what should i modify to work in this new python version?
如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。

绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱,如果其他用户或者作者回复了您的评论,将不能在第一时间通知您!
发布评论
评论(1)
尝试:
似乎在移至
Python 3.9
时,type typer
更改了,并且值不会自动施放到int
中。Try:
Seems that in when moving to
Python 3.9
, thetype inference
changed and the values did not automatically cast intoint
.