替换在Python中具有特定模式的行中所有字符串的问题

发布于 2025-01-28 08:12:07 字数 682 浏览 4 评论 0原文

首先，我说我是Python的新手。

line = "lmn = abc(xyz)/123/.../abc(123)"

line = "abc(xyz) = dlf/hmn/abc(fdg)"

我正在尝试的模式替换示例是abc（xxx）= $ xxx与这些行相符。

我创建的正则是（abc \（）（。*？）（\）） - ＆gt;这很好。现在，如何确保替换发生在一行中的所有位置，因为（。*？？）在行的不同位置有所不同。

我发现我们有re.findall（模式，字符串，flags = 0），它将返回一个元组，我可以用来构建表并替换行。是否有更好的方式可以替代各地的模式？

tmp = re.sub('(abc\\()(.*?)(\\))', '$' **group(1) content**, line , count=???)

上面的问题是我无法在re.sub中使用obj。我称之为

perl，这很简单，一行正则

 =~ s/(abc\\()(.*?)(\\))/(\\$)$2/g

是我可以将我指向一个模块或python中的任何python的文档。顺便说一句..我正在使用Python 3.6

原文

Let me start by saying that i am new to python.

line = "lmn = abc(xyz)/123/.../abc(123)"

line = "abc(xyz) = dlf/hmn/abc(fdg)"

The pattern replacement example I am trying is abc(xxx) = $xxx something along these lines.

The regex I have created is (abc$)(.*?)($) --> this is working fine.
Now how do I ensure the replacement happens in all the places in a line as the (.*?) is different at different places in a line.

I found that we have re.findall(pattern, string, flags=0) which will return a tuple which I can use to construct a table and go with line replacing.
Is there a better way of substituting the pattern everywhere?

tmp = re.sub('(abc\\()(.*?)(\\))', '
The problem with above is I cant use the obj within the re.sub I call
in perl it was simple one line regex
 =~ s/(abc\\()(.*?)(\\))/(\\$)$2/g

Can you please point me to a document for a module or any regex module in python that I can use for this. Btw..I am using python 3.6
 **group(1) content**, line , count=???)

The problem with above is I cant use the obj within the re.sub I call

in perl it was simple one line regex

Can you please point me to a document for a module or any regex module in python that I can use for this. Btw..I am using python 3.6

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嗫嚅 2025-02-04 08:12:07

您可以在sub的替换模式中使用\＆lt;捕获组号来插入捕获组。

因此，如果我正确理解您的问题，这就是您要寻找的：

import re

line1 = "lmn = abc(xyz)/123/.../abc(123)"
line2 = "abc(xyz) = dlf/hmn/abc(fdg)"

# I've simplified the pattern a little to only use two capture groups.
pattern = re.compile(r"(abc\((.*?)\))")

# This is the pattern to replace with: a dollar sign followed by the
# contents of capture group 2.
replacement_pattern = r"$\2"

print(pattern.sub(replacement_pattern, line1)) # lmn = $xyz/123/.../$123
print(pattern.sub(replacement_pattern, line2)) # $xyz = dlf/hmn/$fdg

You can use \<capture group number> in the replacement pattern for sub to insert a capture group.

So if I'm understanding your question correctly, this is what you're looking for:

import re

line1 = "lmn = abc(xyz)/123/.../abc(123)"
line2 = "abc(xyz) = dlf/hmn/abc(fdg)"

# I've simplified the pattern a little to only use two capture groups.
pattern = re.compile(r"(abc\((.*?)\))")

# This is the pattern to replace with: a dollar sign followed by the
# contents of capture group 2.
replacement_pattern = r"$\2"

print(pattern.sub(replacement_pattern, line1)) # lmn = $xyz/123/.../$123
print(pattern.sub(replacement_pattern, line2)) # $xyz = dlf/hmn/$fdg

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