无法从urllib.request.urlopen获得带有dot结尾的响应

发布于 2025-01-28 07:03:14 字数 294 浏览 1 评论 0原文

我的脚本看起来像这样，用户名以“”结尾。点。

import urllib.request

url = "https://likee.video/@evadecarle."
response = urllib.request.urlopen(url)
print(response)

结尾点“”。在URL中似乎会引起问题。如果我将URL更改为url =“ https://likee.video/@11happyness07.12”它可以正常工作。我如何使其与结尾点“”。？

原文

I have a script looking like this, with a username ending with a "." dot.

import urllib.request

url = "https://likee.video/@evadecarle."
response = urllib.request.urlopen(url)
print(response)

The ending dot "." in the url seems to cause a problem.
If I change the url to url = "https://likee.video/@11Happyness07.12" it works fine.
How do I make it work with the ending dot "." ?

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是你 2025-02-04 07:03:14

如果我们尝试获取https://likee.video/@evadecarle。使用urllib.requests，我们会看到：

>>> import urllib.request
>>> response = urllib.request.urlopen('https://likee.video/@evadecarle.')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib64/python3.10/urllib/request.py", line 216, in urlopen
    return opener.open(url, data, timeout)
  File "/usr/lib64/python3.10/urllib/request.py", line 525, in open
    response = meth(req, response)
  File "/usr/lib64/python3.10/urllib/request.py", line 634, in http_response
    response = self.parent.error(
  File "/usr/lib64/python3.10/urllib/request.py", line 563, in error
    return self._call_chain(*args)
  File "/usr/lib64/python3.10/urllib/request.py", line 496, in _call_chain
    result = func(*args)
  File "/usr/lib64/python3.10/urllib/request.py", line 643, in http_error_default
    raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 302: Moved Temporarily
>>>

由于远程网站返回302状态代码，这是失败的
（HTTP重定向）。通常，您会使用一个
httpredirecthandler，类似：

>>> opener = urllib.request.build_opener(urllib.request.HTTPRedirectHandler(), urllib.request.HTTPHandler(debuglevel=0))
>>> resp = opener.open('https://google.com')
>>> resp.url
'https://www.google.com/'

不幸的是，url https://likee.video/@evadecarle。是一个奇怪的
一：它返回302状态代码，但不包括位置：
标识重定向目标的标题。

因此，它看起来像urllib无法正确处理它。
其他人可能会对我纠正我，但看起来请求
库处理此问题没有问题：

>>> resp = requests.get('https://likee.video/@evadecarle.')
>>> resp
<Response [302]>
>>> resp.text[:80]
'<!DOCTYPE html><html lang="en"><head><meta charset="utf-8"><meta name="robots" c'

因此，使用请求模块可能是最简单的解决方案。

If we try to fetch https://likee.video/@evadecarle. using urllib.requests, we see:

>>> import urllib.request
>>> response = urllib.request.urlopen('https://likee.video/@evadecarle.')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib64/python3.10/urllib/request.py", line 216, in urlopen
    return opener.open(url, data, timeout)
  File "/usr/lib64/python3.10/urllib/request.py", line 525, in open
    response = meth(req, response)
  File "/usr/lib64/python3.10/urllib/request.py", line 634, in http_response
    response = self.parent.error(
  File "/usr/lib64/python3.10/urllib/request.py", line 563, in error
    return self._call_chain(*args)
  File "/usr/lib64/python3.10/urllib/request.py", line 496, in _call_chain
    result = func(*args)
  File "/usr/lib64/python3.10/urllib/request.py", line 643, in http_error_default
    raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 302: Moved Temporarily
>>>

It's failing because the remote website is returning a 302 status code
(an http redirect). Normally, you would handle this by using an
HTTPRedirectHandler, something like:

>>> opener = urllib.request.build_opener(urllib.request.HTTPRedirectHandler(), urllib.request.HTTPHandler(debuglevel=0))
>>> resp = opener.open('https://google.com')
>>> resp.url
'https://www.google.com/'

Unfortunately, the URL https://likee.video/@evadecarle. is an odd
one: it returns a 302 status code, but doesn't include a Location:
header identifying the redirect target.

Because of this, it looks like urllib doesn't handle it properly.
Someone else may correct me on this, but it looks like the requests
library handles this without a problem:

>>> resp = requests.get('https://likee.video/@evadecarle.')
>>> resp
<Response [302]>
>>> resp.text[:80]
'<!DOCTYPE html><html lang="en"><head><meta charset="utf-8"><meta name="robots" c'

So using the requests module may be the simplest solution.

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