在未单击的情况下调用MUI DataGrid中的按钮ONCLICK

Question

我在MUI V5 DataGrid中实现了一个按钮。基于官方样本 https://mui.com/x/x/ React-Data-Grid/columns/＃Render-cell ，我在按钮中添加了onclick。

首次渲染单元格而不是单击事件时，调用了OnClick功能。

const downloadSearchResult = (params) => {
  const link = document.createElement("a");
  link.download = "download.txt"
  link.href = "./download.txt";
  link.click();
}

const notes = [
  {id: 1, Search_result: "download.txt" },
  {id: 2, Search_result: "pending" },
  {id: 3, Search_result: "pending" },
]

export default function Notes() {
  var show
  const columns: GridColDef [] = [
    { field: 'Search_result', headerName: 'Search result', width: 150,
      renderCell: (params) => (
        <strong>
          {show = (params.value == "Pending")}
          {show && params.value}
          {{!show && 
            <Button 
              variant="contained" size="small"
              onClick={downloadSearchResult(params)}
            >
              Download
            </Button>}}
        </strong>
      )
    },
  ];
  
  return (
    <Container>
      <div>
        <DataGrid rows={notes} columns={columns} />
      </div>      
    </Container>
  )
}

呼叫堆栈中的onClick函数：

in Mui v5 datagrid：

Answer 1

尝试

  <Button 
          variant="contained" size="small"
          onClick={()=>downloadSearchResult(params)}
        >