使用http请求ifconfig.co获取与Java中私有IP相关联的公共IP

Question

我编写了一个代码，以获取与每个接口相关联的所有私人IP。我正在将所有私人IP存储在arraylist ips中。

List<String> ips = new ArrayList<>();
for (Enumeration<NetworkInterface> en = NetworkInterface.getNetworkInterfaces(); en.hasMoreElements();) {
       NetworkInterface intf = en.nextElement();
       for (Enumeration<InetAddress> enumIpAddr = intf.getInetAddresses(); enumIpAddr.hasMoreElements(); ) {
                    ips.add(enumIpAddr.nextElement().toString().replace("/", ""));
       }
}

现在，我想在列表中迭代IPS，并想调用HTTP请求以获取公共IP。以下是Linux Curl命令，它将返回与私有IP 10.74.4.11关联的公共IP。

curl -i --interface 10.74.4.11 "ifconfig.co"

我只想将此linux命令转换为可以在程序中使用的Java HTTP请求。

Answer 1

此方法使用Java Runtime API执行命令，然后将发现的公共IP添加到Hashmap中，作为内部Internip密钥的值。因此，最后，您可以通过搜索hashmap“ ips.get（“ internalip”）”来找到所需的公共IP。

private static void getIps() throws IOException {
            Map<String, String> ips = new HashMap<>();
            for (Enumeration<NetworkInterface> en = NetworkInterface.getNetworkInterfaces(); en.hasMoreElements();) {
                NetworkInterface intf = en.nextElement();
                for (Enumeration<InetAddress> enumIpAddr = intf.getInetAddresses(); enumIpAddr.hasMoreElements(); ) {
                    ips.put(enumIpAddr.nextElement().toString().replace("/", ""), "");
                }
            }
            for (String ip: ips.keySet())
            {
                String command="curl --interface "+ ip+" ifconfig.co";
                System.out.println("Excecuting: "+command);
                Process process = Runtime.getRuntime().exec(command);
                try {
                    process.waitFor();
                    final int exitValue = process.waitFor();
                    if (exitValue == 0) {
                        System.out.println("Successfully executed the command: " + command);
                       List<String> result = new BufferedReader(new InputStreamReader(process.getInputStream()))
                        .lines().collect(Collectors.toList());
                       ips.put(ip, result.get(result.size()-1));//the public IP will be the last item in the result stream
                    }
                    else {
                        System.out.println("Failed to execute the following command: " + command + " due to the following error(s):");
                        try (final BufferedReader b = new BufferedReader(new InputStreamReader(process.getErrorStream()))) {
                            String line;
                            if ((line = b.readLine()) != null)
                                System.out.println(line);
                        } catch (final IOException e) {
                            e.printStackTrace();
                        }
                    }
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }



            }
            System.out.println(ips);

        }