如何创建多个50便士硬币

Question

如何在不重叠或不互动的页面中创建单独的硬币。下面的代码显示了重叠的硬币，如果数字大于2。

import turtle

tegan = turtle.Turtle()

turtle.fillcolor('grey')

turtle.begin_fill()


numbers = int(input("How many 50 pence coins you have: "))
print(numbers)

length = 100  
degrees = 51.42857
angle = 40

def draw_heptagon(tegan, length, numbers, angle):

    for i in range(numbers):
        for x in range(7):
            turtle.forward(length)
            turtle.left(degrees)
        turtle.right(angle)

draw_heptagon(tegan, length, numbers, angle)

turtle.end_fill()
turtle.done()

Answer 1

这是您可以完善的大概方法。我们将跟踪我们绘制的随机放置的七琴的中心。我们将它们视为圆圈，以绘制和检查它们之间的距离：

from turtle import Screen, Turtle
from random import randint

RADIUS = 100
ANGLE = 40

number = int(input("How many 50 pence coins you have: "))

def draw_heptagons(t, number):
    coins = []

    for _ in range(number):
        while True:
            x = randint(RADIUS - width/2, width/2 - RADIUS)
            y = randint(RADIUS - height/2, height/2 - RADIUS)

            t.goto(x, y)
            t.right(ANGLE)

            if coins and any(t.distance(position) < RADIUS * 2 for position in coins):
                continue

            break

        t.right(90)
        t.forward(RADIUS)  # draw heptagon centered at x, y
        t.left(90)

        turtle.begin_fill()
        t.circle(RADIUS, steps=7)
        turtle.end_fill()

        coins.append((x, y))

screen = Screen()
width, height = screen.window_width(), screen.window_height()

turtle = Turtle()
turtle.speed('fastest')  # because I have no patience
turtle.penup()

draw_heptagons(turtle, number)

turtle.hideturtle()
screen.exitonclick()

这做了您所描述的，但是七个人实际上可能比圆圈更接近（窗口中更多），因此您需要修改测试，以及您在位置中存储的哪些信息，如果要更紧：

< img src =“ https://i.sstatic.net/tkmgj.png” alt =“在此处输入图像说明”>