生成Shell Split split命名配置文件的设置名称数

发布于 2025-01-27 04:19:53 字数 790 浏览 2 评论 0原文

好的，因此，当您从终端运行拆分函数时，它会生成名称，其名称为以x开头的所有零件，然后是2个字母字母顺序的增量对。 aa，ab，acct。

我要o的是使用python和一个数字生成这些名称的列表。

n=3
#['xaa', 'xab', 'xac']

n = 5
#['xaa', 'xab', 'xac', 'xad', 'xae']

到目前为止

import string

n=30
myNum = round((n/26) + (0.5))
list1 = list(string.ascii_lowercase)*myNum

list1 = list1[:n]

list2sring=""
for i in list1:
 list2sring=list2sring+i+" "

newstring = "a" + list2sring.strip().replace(" "," a")
print("x" + newstring.replace(" "," x"))

#xaa xab xac xad xae xaf xag xah xai xaj xak xal xam xan xao xap xaq xar xas xat xau xav xaw xax xay xaz xaa xab xac xad

xaa xab xac xad xae xaf xag xah xai xaj xak xal xam xan xao xap xaq xar xas xat xau xav xaw xax xay xaz xba xbb xbc xbd

原文

ok so when you run the split function from terminal it generates the names it names all the parts starting with an x followed by an 2 letter alphabetical incremental pair.
aa,ab,ac ect.

What I am looking to o is generate a list of these names using python and a number.

n=3
#['xaa', 'xab', 'xac']

n = 5
#['xaa', 'xab', 'xac', 'xad', 'xae']

So far I am able to generate enough base numbers off of a number but need to find a way to change the second letter I append for every instance of 'z'

import string

n=30
myNum = round((n/26) + (0.5))
list1 = list(string.ascii_lowercase)*myNum

list1 = list1[:n]

list2sring=""
for i in list1:
 list2sring=list2sring+i+" "

newstring = "a" + list2sring.strip().replace(" "," a")
print("x" + newstring.replace(" "," x"))

#xaa xab xac xad xae xaf xag xah xai xaj xak xal xam xan xao xap xaq xar xas xat xau xav xaw xax xay xaz xaa xab xac xad

Desired Output:

xaa xab xac xad xae xaf xag xah xai xaj xak xal xam xan xao xap xaq xar xas xat xau xav xaw xax xay xaz xba xbb xbc xbd

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白云悠悠 2025-02-03 04:19:54

您可以使用string.ascii_lowercase，itertools.products.product和字符串格式来完成您想要的工作。

from string import ascii_lowercase
from itertools import product

def make_patterns(n):
    letters_iter = product(ascii_lowercase, ascii_lowercase)
    return [
        f'x{a}{b}'
        for _, (a, b) in zip(range(n), letters_iter)
    ]

make_patterns(5)
# returns:
['xaa', 'xab', 'xac', 'xad', 'xae']

如果您希望它作为打印字符串：

print(' '.join(make_patterns(5)))
# prints:
xaa xab xac xad xae

You can use string.ascii_lowercase, itertools.product, and string formatting to do what you want.

from string import ascii_lowercase
from itertools import product

def make_patterns(n):
    letters_iter = product(ascii_lowercase, ascii_lowercase)
    return [
        f'x{a}{b}'
        for _, (a, b) in zip(range(n), letters_iter)
    ]

make_patterns(5)
# returns:
['xaa', 'xab', 'xac', 'xad', 'xae']

If you want it as one string for printing:

print(' '.join(make_patterns(5)))
# prints:
xaa xab xac xad xae

回复收藏 0 原文

颜 2025-02-03 04:19:54

您可以将list2sring拆分为字符列表，然后将其附加到手动串行的for循环中

import string

n=30
myNum = round((n/26) + (0.5))
list1 = list(string.ascii_lowercase)*myNum
print(string.ascii_lowercase)

list1 = list1[:n]

list2sring=""
for i in list1:
 list2sring=list2sring+i+" "

chars = list2sring.strip().split(" ")
newstring = ""
i = 0
for c in chars:
    newstring += " x" + string.ascii_lowercase[i] + c
    if c == "z":
        i = (i + 1) % 26

print(newstring.strip())

You can split list2sring into list of chars and append it to string manually in the for loop

import string

n=30
myNum = round((n/26) + (0.5))
list1 = list(string.ascii_lowercase)*myNum
print(string.ascii_lowercase)

list1 = list1[:n]

list2sring=""
for i in list1:
 list2sring=list2sring+i+" "

chars = list2sring.strip().split(" ")
newstring = ""
i = 0
for c in chars:
    newstring += " x" + string.ascii_lowercase[i] + c
    if c == "z":
        i = (i + 1) % 26

print(newstring.strip())

回复收藏 0 原文

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