从列表中读书
import numpy as np
filename = 'input1.txt'
output_file = 'output.txt'
delimiters = ',.?!'
with open(filename, 'r') as f:
text = f.read()
for delimiter in delimiters:
text = text.replace(delimiter, ',')
lines = text.split('\n')
parts = list()
print(lines)
我希望所有包含文本 /数字的行都在表示
例中,我有一个输入文件。文本文件,
1,2,3,4,5,6
7,8,9,10,11,12
13,14,15,16,17
我
['1,2,3,4,5,6', '7,8,9,10,11,12', '13, 14,15,16,17 ',' ',' ',' ', '', '', '', '', '']
正在寻找从后面的退出来阅读行,
['13, 14,15,16,17', '7,8,9,10,11,12', '1,2,3,4,5,6', '', '', '', '', '', '', '']
谢谢您的帮助
import numpy as np
filename = 'input1.txt'
output_file = 'output.txt'
delimiters = ',.?!'
with open(filename, 'r') as f:
text = f.read()
for delimiter in delimiters:
text = text.replace(delimiter, ',')
lines = text.split('\n')
parts = list()
print(lines)
I want all the lines containing text / numbers from the back to be in the sheet
example I have an input.text file
1,2,3,4,5,6
7,8,9,10,11,12
13,14,15,16,17
this give me
['1,2,3,4,5,6', '7,8,9,10,11,12', '13, 14,15,16,17 ',' ',' ',' ', '', '', '', '', '']
I'm looking for an exit from behind to read the lines
['13, 14,15,16,17', '7,8,9,10,11,12', '1,2,3,4,5,6', '', '', '', '', '', '', '']
Thank you for your help
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在Python中反转列表:
您的情况:
Reverse a list in Python:
Your case: