在嘲笑函数中返回Promise＆lt; string [] |从不

Question

我正在使用React+Jest测试现有组件。它具有类似的函数过滤器：

const filterEmptyDeliveries = (arr): Promise<string[] | never> => {
    if (arr.length === 0) {
      return Promise.reject("empty") as any as Promise<never>
    }
    return Promise.resolve(arr) as Promise<string[]>
  }

在我的组件中，我称其为这样：

const whiteListArr = []
const setupDeliveryType = async () => {
   const tempAsin = [] // Empty or Not Empty
    try {
       ... other code
      if (tempAsin.length !== 0) {
        if (whiteListArr.length === 0) {
          whiteListArr.push(... some list computed above)
        } else {
          await filterEmptyDeliveries(asinWhiteList)
        }
       } else {
         await filterEmptyDeliveries(whiteListArr)
      } 
    } catch (err) {
      console.log(err)
    } finally {
      setLoading(false)
    }
  }

这就是我在测试中嘲笑我

const filterEmptyDeliveries = jest.fn()
filterEmptyDeliveries.mockResolvedValue(['A12334567'])

it('calls setupDeliveryType ', async () => {
      const wrapper = mount(<Component / >)
      await act(flushPromises)
      wrapper.update()
      await act(flushPromises)

      const whiteList = ['B00000000']
      ... other tests that pass so i'm pretty confident the code reaches here
      await act(flushPromises)
      expect(filterEmptyDeliveries).toHaveBeenCalled() // Fails

     /// Fails with
      Expected number of calls: >= 1
      Received number of calls:    0

    })

在哪里出错的方式？

Answer 1

您正在模拟一个称为filterDelive的函数，但是该组件正在调用filteremptydeliveries。