如何通过字节号在node.js中创建位掩码？

发布于 2025-01-26 12:12:12 字数 522 浏览 4 评论 0原文

我有一个字符串：0x55739DC6385D81C53D462A255A17C6BD9A71AA68。

而且我还有一个需要实现的函数：

const caller = '0x55739dC6385d81c53d462a255a17C6bd9A71Aa68';
const from = 160;
const to = 96;

const getCallerMask = (from, to, caller) => {
    // need to get mask by from, to on the "caller" string and move bytes to the right by "to" argument
}

这是该函数应该做的：

Mask(160, 96, caller) >> 96

我什至不知道上面的哪种语言，但我想它应该从字符串中拿起字节蒙版并移动指针到右侧的96个字节。有没有办法在node.js中实现它？

原文

I have a string: 0x55739dC6385d81c53d462a255a17C6bd9A71Aa68.

And also I have a function that I need to implement:

const caller = '0x55739dC6385d81c53d462a255a17C6bd9A71Aa68';
const from = 160;
const to = 96;

const getCallerMask = (from, to, caller) => {
    // need to get mask by from, to on the "caller" string and move bytes to the right by "to" argument
}

This is what the function should do:

Mask(160, 96, caller) >> 96

I don't even know in which language the example above, but I guess that it should take the byte mask from the string and move the pointer to 96 bytes to the right. Is there a way to implement it in node.js?

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