保存数据帧名称，然后在后续代码中引用该对象
想引用存储在对象中的数据框架名称，例如：
dfName <- 'mydf1'
dfName <- data.frame(c(x = 5)) #want dfName to resolve to 'mydf1', not create a dataframe named 'dfName'
mydf1
相反：我得到：错误：object'mydf1'找不到
更正的方案：
olddf <- data.frame(c(y = 8))
mydf1 <- data.frame(c(x = 5))
assign('dfName', mydf1)
dfName <- olddf #why isnt this the same as doing "mydf1 <- olddf"?
我不想引用名为“ dfname “，而是”，“ mydf1”。
更新 我为我想做的事情找到了一个笨拙的解决方法。代码是：
olddf <- data.frame(x = 8)
olddfName <- 'olddf'
newdfName <- 'mydf1'
statement <- paste(newdfName, "<-", olddfName, sep = " ")
writeLines(statement, "mycode.R")
source("mycode.R")
任何人都有更优雅的方式，尤其是不诉诸写/来源的情况？
Would like to reference a dataframe name stored in an object, such as:
dfName <- 'mydf1'
dfName <- data.frame(c(x = 5)) #want dfName to resolve to 'mydf1', not create a dataframe named 'dfName'
mydf1
Instead, I get: Error: object 'mydf1' not found
CORRECTED SCENARIO:
olddf <- data.frame(c(y = 8))
mydf1 <- data.frame(c(x = 5))
assign('dfName', mydf1)
dfName <- olddf #why isnt this the same as doing "mydf1 <- olddf"?
I don't want to reference an actual dataframe named "dfName", rather "mydf1".
UPDATE
I have found a clunky workaround for what I wanted to do. The code is:
olddf <- data.frame(x = 8)
olddfName <- 'olddf'
newdfName <- 'mydf1'
statement <- paste(newdfName, "<-", olddfName, sep = " ")
writeLines(statement, "mycode.R")
source("mycode.R")
Anyone have a more elegant way, especially without resorting to a write/source?
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我猜您想将多个
data.frames存储在循环中或类似过程中。在这种情况下，将它们存储在命名list中更加有效，并且更好。但是，您可以通过分配来实现自己的目标I am guessing you want to store multiple
data.frames in a loop or similar. In that case it is much more efficient and better to store them in a namedlist. However, you can achieve your goal withassign