如何比较两个表的计数

发布于 2025-01-26 07:40:17 字数 1701 浏览 3 评论 0原文

让Troble试图比较两个表(使用SQLite)的计数。

假设我有:

primary键)

numIdobject_category
1永久
2借用
3借用
4借用
5借用

okipts(numId is (numobj是 emern键/主键参考对象表)

numobjcollection_name
2collection_alpha
3collection_betha
4collection_betha collection_betha
5collection_betha

查询我需要执行的是:

“借入的对象数量比 数量的永久性objet?”

我目前的尝试是:

SELECT Collection_name FROM Borrowed
WHERE (SELECT COUNT(Collection_name) FROM Borrowed)> 
(SELECT COUNT(*) FROM Objects WHERE Object_category = 
'permanent')

它正在返回列中的值,而不是按照假定的方式工作(HOL应该返回拥有3个对象的'Collection_Betha',大于现有的永久对象的数量,即1)。

Having troble trying to compare count from two tables (using SQLite).

Supposing I have tables like:

Objects (NumId is Primary key)

NumIdObject_category
1permanent
2borrowed
3borrowed
4borrowed
5borrowed

Borrowed
(NumObj is Foreign Key/Primary Key referring Object table)

NumObjCollection_name
2collection_alpha
3collection_betha
4collection_betha
5collection_betha

Query I need to perform is:

"What are the collections with higher number of borrowed objects than
quantity of permanent objets?"

My current attempt is:

SELECT Collection_name FROM Borrowed
WHERE (SELECT COUNT(Collection_name) FROM Borrowed)> 
(SELECT COUNT(*) FROM Objects WHERE Object_category = 
'permanent')

It is returning the values from the column, not working as supposed (hould have returned the 'collection_betha' for owning 3 objects, greater than number of existing permanent objects that is 1).

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评论(2

岁月染过的梦 2025-02-02 07:40:17

也许加入会有所帮助

SELECT Borrowed.Collection_name
FROM Borrowed 
JOIN Objects 
ON Objects.NumId= Borrowed.NumObj
GROUP BY Borrowed.Collection_name 
HAVING COUNT(NumObj) > 
(SELECT COUNT(*) FROM Objects WHERE Object_category = 'permanent')

Maybe a join will help

SELECT Borrowed.Collection_name
FROM Borrowed 
JOIN Objects 
ON Objects.NumId= Borrowed.NumObj
GROUP BY Borrowed.Collection_name 
HAVING COUNT(NumObj) > 
(SELECT COUNT(*) FROM Objects WHERE Object_category = 'permanent')
芸娘子的小脾气 2025-02-02 07:40:17

我将在这里使用有条件的聚合:

SELECT b.Collection_name
FROM Borrowed b
INNER JOIN Objects o
    ON o.NumId = b.NumObj
GROUP BY b.Collection_name
HAVING SUM(o.Object_category = 'borrowed') > SUM(o.Object_category = 'permanent');

I would use conditional aggregation here:

SELECT b.Collection_name
FROM Borrowed b
INNER JOIN Objects o
    ON o.NumId = b.NumObj
GROUP BY b.Collection_name
HAVING SUM(o.Object_category = 'borrowed') > SUM(o.Object_category = 'permanent');
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