用XOR 15转换输入

Question

我正在尝试使用三种不同类型或密码的密码输入，并且我完全卡在XOR 15上。

import string

def caesar(text, shift, alphabets):

    def shift_alphabet(alphabet):
        return alphabet[shift:] + alphabet[:shift]

    shifted_alphabets = tuple(map(shift_alphabet, alphabets))
    final_alphabet = ''.join(alphabets)
    final_shifted_alphabet = ''.join(shifted_alphabets)
    table = str.maketrans(final_alphabet, final_shifted_alphabet)
    return text.translate(table)

plaintext = input("Enter a sentence to encode: >")
shifted = int(input("Shift by how much? >"))

print("Caesar results:")
print("Original: ", plaintext)
print("Cipher: ",(caesar(plaintext, shifted, [string.printable])))

def rot13(text):
    return ''.join([chr((ord(letter) - 97 + 13) % 26 + 97)
                    if 97 <= ord(letter) <= 122
                    else letter
                for letter in text.lower()])
print("Rot13 results: ")
print("Original: ", plaintext)
print("Rot13:",(rot13(plaintext))) 


def xor(plaintext,number):
    L = list(plaintext)
    L2 = [ord(value) ^ number for value in L]
    return L2

i = plaintext.encode('utf-8')
xor_number = 00;
results = xor(plaintext,xor_number)
print ("XOR 15 results:")
print ("Original hex:", i.hex(' '))
print ("XOR 15 hex:",  results)

当我在用户输入后获得结果时，我只会获得常规的ASCII值，而不是原始HEX的XOR 15 。我要去哪里？

当前结果：

XOR 15 results:
Original hex: 41 42 44 20 78 79 7a 20 31 32 33 21
XOR 15 hex: [65, 66, 68, 32, 120, 121, 122, 32, 49, 50, 51, 33]

预期结果：

XOR 15 results:
Original hex: 41 42 44 20 78 79 7a 20 31 32 33 21
XOR 15 hex: [be, bd, bc, df, 87, 86, 85, df, ce, cd, cc, de]