在3D中绘制无法正确渲染

发布于 2025-01-26 06:04:05 字数 3094 浏览 3 评论 0原文

我正在尝试在3D空间(在Python中)中绘制许多组件,但是渲染问题有问题。例如,下面的代码绘制了一个球体,其表面上有一些点,其赤道周围有一个环,以及各种箭头从原点射出。但是,matplotlib正在呈现所有点/球的顶部的箭头,并且基于在球体内部或外部的内部或外部没有正确的阴影。有更好的方法吗?我愿意在需要时使用其他图书馆,但没有成功地看起来不错。

import matplotlib.pyplot as plt
import numpy as np
from matplotlib.patches import FancyArrowPatch
from mpl_toolkits.mplot3d import proj3d

class Arrow3D(FancyArrowPatch):
    def __init__(self, xs, ys, zs, *args, **kwargs):
        super().__init__((0,0), (0,0), *args, **kwargs)
        self._verts3d = xs, ys, zs

    def do_3d_projection(self, renderer=None):
        xs3d, ys3d, zs3d = self._verts3d
        xs, ys, zs = proj3d.proj_transform(xs3d, ys3d, zs3d, self.axes.M)
        self.set_positions((xs[0],ys[0]),(xs[1],ys[1]))

        return np.min(zs)

def arrow3d(ax, length=1, width=0.05, head=0.2, headwidth=2,
                theta_x=0, theta_z=0, offset=(0,0,0), **kw):
    w = width
    h = head
    hw = headwidth
    theta_x = np.deg2rad(theta_x)
    theta_z = np.deg2rad(theta_z)

    a = [[0,0],[w,0],[w,(1-h)*length],[hw*w,(1-h)*length],[0,length]]
    a = np.array(a)

    r, theta = np.meshgrid(a[:,0], np.linspace(0,2*np.pi,30))
    z = np.tile(a[:,1],r.shape[0]).reshape(r.shape)
    x = r*np.sin(theta)
    y = r*np.cos(theta)

    rot_x = np.array([[1,0,0],[0,np.cos(theta_x),-np.sin(theta_x) ],
                      [0,np.sin(theta_x) ,np.cos(theta_x) ]])
    rot_z = np.array([[np.cos(theta_z),-np.sin(theta_z),0 ],
                      [np.sin(theta_z) ,np.cos(theta_z),0 ],[0,0,1]])

    b1 = np.dot(rot_x, np.c_[x.flatten(),y.flatten(),z.flatten()].T)
    b2 = np.dot(rot_z, b1)
    b2 = b2.T+np.array(offset)
    x = b2[:,0].reshape(r.shape); 
    y = b2[:,1].reshape(r.shape); 
    z = b2[:,2].reshape(r.shape); 
    ax.plot_surface(x,y,z, **kw)

# Create a sphere
r = 1
pi = np.pi
cos = np.cos
sin = np.sin
phi, theta = np.mgrid[0.0:pi:30j, 0.0:2.0*pi:30j]
x = r*sin(phi)*cos(theta)
y = r*sin(phi)*sin(theta)
z = r*cos(phi)

#Set colours and render
fig = plt.figure(figsize=(8,8))
ax = fig.add_subplot(111, projection='3d')

ax.plot_surface(x, y, z,  rstride=1, cstride=1, color='c', alpha=0.3, linewidth=0)

theta = np.linspace(0, 2*np.pi, 100)
ax.plot(np.cos(theta), np.sin(theta), 0, 'k', linewidth=4)

ax.scatter(x,y,z,color="k",s=20)

eig_vec = np.array([[1., 0., 0.],
       [0., 1., 0.],
       [0., 0., 1.]])
for v in eig_vec:
    #ax.plot([mean_x,v[0]], [mean_y,v[1]], [mean_z,v[2]], color='red', alpha=0.8, lw=3)
    #I will replace this line with:
    a = Arrow3D([0, v[0]], [0, v[1]], 
                [0, v[2]], mutation_scale=20, 
                lw=3, arrowstyle="-|>", color="r")
    ax.add_artist(a)

arrow3d(ax, length=2.5, width=0.02, head=0.1, headwidth=1.5, offset=[0,0,0], 
        theta_x=40,  color="crimson")

ax.set_xlim([-1,1])
ax.set_ylim([-1,1])
ax.set_zlim([-1,1])
ax.set_aspect("auto")
plt.tight_layout()
plt.show()

I am trying to plot a number of components in 3d space (in python), but am having issues with the rendering. As an example, the code below plots a sphere with some points on its surface, a ring around its equator, and a variety of arrows going radially out from the origin. However, matplotlib is rendering the arrows on top of all the points/sphere and does not shade them correctly based on being inside or outside the sphere. Is there a better way to do this? I am open to using other libraries if needed, but have not had much success getting anything to look good.

import matplotlib.pyplot as plt
import numpy as np
from matplotlib.patches import FancyArrowPatch
from mpl_toolkits.mplot3d import proj3d

class Arrow3D(FancyArrowPatch):
    def __init__(self, xs, ys, zs, *args, **kwargs):
        super().__init__((0,0), (0,0), *args, **kwargs)
        self._verts3d = xs, ys, zs

    def do_3d_projection(self, renderer=None):
        xs3d, ys3d, zs3d = self._verts3d
        xs, ys, zs = proj3d.proj_transform(xs3d, ys3d, zs3d, self.axes.M)
        self.set_positions((xs[0],ys[0]),(xs[1],ys[1]))

        return np.min(zs)

def arrow3d(ax, length=1, width=0.05, head=0.2, headwidth=2,
                theta_x=0, theta_z=0, offset=(0,0,0), **kw):
    w = width
    h = head
    hw = headwidth
    theta_x = np.deg2rad(theta_x)
    theta_z = np.deg2rad(theta_z)

    a = [[0,0],[w,0],[w,(1-h)*length],[hw*w,(1-h)*length],[0,length]]
    a = np.array(a)

    r, theta = np.meshgrid(a[:,0], np.linspace(0,2*np.pi,30))
    z = np.tile(a[:,1],r.shape[0]).reshape(r.shape)
    x = r*np.sin(theta)
    y = r*np.cos(theta)

    rot_x = np.array([[1,0,0],[0,np.cos(theta_x),-np.sin(theta_x) ],
                      [0,np.sin(theta_x) ,np.cos(theta_x) ]])
    rot_z = np.array([[np.cos(theta_z),-np.sin(theta_z),0 ],
                      [np.sin(theta_z) ,np.cos(theta_z),0 ],[0,0,1]])

    b1 = np.dot(rot_x, np.c_[x.flatten(),y.flatten(),z.flatten()].T)
    b2 = np.dot(rot_z, b1)
    b2 = b2.T+np.array(offset)
    x = b2[:,0].reshape(r.shape); 
    y = b2[:,1].reshape(r.shape); 
    z = b2[:,2].reshape(r.shape); 
    ax.plot_surface(x,y,z, **kw)

# Create a sphere
r = 1
pi = np.pi
cos = np.cos
sin = np.sin
phi, theta = np.mgrid[0.0:pi:30j, 0.0:2.0*pi:30j]
x = r*sin(phi)*cos(theta)
y = r*sin(phi)*sin(theta)
z = r*cos(phi)

#Set colours and render
fig = plt.figure(figsize=(8,8))
ax = fig.add_subplot(111, projection='3d')

ax.plot_surface(x, y, z,  rstride=1, cstride=1, color='c', alpha=0.3, linewidth=0)

theta = np.linspace(0, 2*np.pi, 100)
ax.plot(np.cos(theta), np.sin(theta), 0, 'k', linewidth=4)

ax.scatter(x,y,z,color="k",s=20)

eig_vec = np.array([[1., 0., 0.],
       [0., 1., 0.],
       [0., 0., 1.]])
for v in eig_vec:
    #ax.plot([mean_x,v[0]], [mean_y,v[1]], [mean_z,v[2]], color='red', alpha=0.8, lw=3)
    #I will replace this line with:
    a = Arrow3D([0, v[0]], [0, v[1]], 
                [0, v[2]], mutation_scale=20, 
                lw=3, arrowstyle="-|>", color="r")
    ax.add_artist(a)

arrow3d(ax, length=2.5, width=0.02, head=0.1, headwidth=1.5, offset=[0,0,0], 
        theta_x=40,  color="crimson")

ax.set_xlim([-1,1])
ax.set_ylim([-1,1])
ax.set_zlim([-1,1])
ax.set_aspect("auto")
plt.tight_layout()
plt.show()

3dplot

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