C＆＃x2B;＆＃x2B;不存在从输入到LPINPUT的合适转换功能

发布于 2025-01-26 05:21:13 字数 635 浏览 2 评论 0原文

我正在尝试获取鼠标的坐标，然后将鼠标相对移动到这些坐标。

#include <stdio.h>
#include <windows.h>
#include <stdlib.h>

int main() {
    SHORT f5;
    POINT pt{};
    MOUSEINPUT _mi{};
    INPUT mm{};
    mm.type = 0;
    for (;;) {
        f5 = GetAsyncKeyState(0x74);
        if (f5 > 0) {
            GetCursorPos(&pt);
            _mi.dx = pt.x + 100;
            _mi.dy = pt.y + 100;
            mm.mi = _mi;
            SendInput(1, mm, sizeof(mm));   
        }
        Sleep(50);
    }
    return 0;
}

我遇到了一个错误，说不存在从输入到LPINPUT的合适转换，但我也不知道如何创建“ LPINPUT”结构。

原文

i'm trying to get the coordinates of the mouse, then move the mouse relative to those coordinates.

#include <stdio.h>
#include <windows.h>
#include <stdlib.h>

int main() {
    SHORT f5;
    POINT pt{};
    MOUSEINPUT _mi{};
    INPUT mm{};
    mm.type = 0;
    for (;;) {
        f5 = GetAsyncKeyState(0x74);
        if (f5 > 0) {
            GetCursorPos(&pt);
            _mi.dx = pt.x + 100;
            _mi.dy = pt.y + 100;
            mm.mi = _mi;
            SendInput(1, mm, sizeof(mm));   
        }
        Sleep(50);
    }
    return 0;
}

I'm getting an error saying that no suitable conversion from INPUT to LPINPUT exists, but I also have no idea how to create a "LPINPUT" struct.

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心不设防 2025-02-02 05:21:13

sendInput（）期望指向Input结构的数组。由于您仅传递1 输入，请将其作为指针的地址作为指针，通过将结构与>＆amp;运算符相结合，只需就像getCursorPos（）一样：

SendInput(1, &mm, sizeof(mm));

SendInput() expects a pointer to an array of INPUT structures. Since you are passing only 1 INPUT, give it the address of your INPUT as a pointer by prefixing the structure with the & operator, just as you did with GetCursorPos():