如何通过PowerShell中的功能更改脚本划分的变量？

发布于 2025-01-26 03:40:52 字数 288 浏览 2 评论 0 原文

让脚本

[int] $num01 = 2

function setNo ([int] $num02)
{
    $num01 = $num02;
}

write-host $num01

setNo -num02 4

write-host $num01

setNo -num02 6

write-host $num01

产生输出

2
2
2

如何使其产生输出：

2
4
6

原文

Have the script

[int] $num01 = 2

function setNo ([int] $num02)
{
    $num01 = $num02;
}

write-host $num01

setNo -num02 4

write-host $num01

setNo -num02 6

write-host $num01

It produces an output

2
2
2

How to make it produce output:

2
4
6

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浅沫记忆 2025-02-02 03:40:52

有几种方法可以改变函数范围之外的变量值，例如：

by reference ：

([ref] $num01).Value = $num02;

使用

$script:num01 = $num02;

/Powershell/module/microsoft.powershell.utility/set-variable?view=powershell-7.2#:%7e:text=the%20set; rel =“ nofollow noreferrer”> set-variable 带有 -scope脚本参数或 $ executionContext ：

Set-Variable num01 -Value $num02 -Scope Script
# OR
$ExecutionContext.SessionState.PSVariable.Set('script:num01', $num02)

请注意，请注意，在此中，特定情况，以上是必要的，因为外部变量 $ num01 是 scalarar ，如果是 non-scalar < /em>，即阵列或哈希表：

$num01 = @(2) # => array of a single element, index 0

function setNo ([int] $num02) {
    $num01[0] = $num02 # => updating index 0 of the array
}

setNo 10; $num01 # => 10

There are several ways of altering the value of a variable outside the function's scope, for example:

By reference:

([ref] $num01).Value = $num02;

Using a Scope Modifier:

$script:num01 = $num02;

Using Set-Variable with the -Scope Script argument or $ExecutionContext:

Set-Variable num01 -Value $num02 -Scope Script
# OR
$ExecutionContext.SessionState.PSVariable.Set('script:num01', $num02)

Note that, in this particular case, one of the above is necessary because the outside variable $num01 is a scalar, it would not be the case if it was a non-scalar, i.e. an array or hash table:

$num01 = @(2) # => array of a single element, index 0

function setNo ([int] $num02) {
    $num01[0] = $num02 # => updating index 0 of the array
}

setNo 10; $num01 # => 10

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