在文本文件的不同部分中计算单词

Question

对于一个项目，我必须与Python分析具有200多个简历的TXT文件。我必须搜索文件，并必须计算是否提到了特定键。这是我非常简单的代码：

file = open("CVC.txt")

data=file.read()

occurence = data.count("Biology")

print('Number of occurrences of the word :', occurence) 

问题是当我在一个简历中搜索EG Enginnerser几次。但是我只想计算一次。每个简历都以“联系”一词开头。我的问题是如何指定可以区分简历的算法，并且仅计入简历中的特定关键字。

提前致谢！

ex1 ex2

Answer 1

逻辑有些简单。解析文件的每一行，当您看到启动联系人的行时，然后存储该行，然后全部存储直到您看到下一个联系人行。读取文件后，将剩余的行存储为最后一个开始联系的一部分。

contacts = []
current_contact = None

with open("CVC.txt") as data:

    for line in data.splitlines():
      # skip page lines (e.g. in middle of a contact)
      if line.strip().startswith("Page "):
        continue
      # start a new contact
      if line.strip() == "Contact":
        if current_contact is not None:
          # store the current contact lines, if they exist
          contacts.append('\n'.join(current_contact))
        current_contact = []
        continue
      # collect all lines for a single contact
      if current_contact is not None:
        current_contact.append(line.rstrip())
      else:
        print(f"Not seen 'Contact' yet... '{line.rstrip()}'")  # for debugging, e.g. start of the file
    # store remaining data after all lines are read
    if current_contact:
      contacts.append('\n'.join(current_contact))
      del current_contact

我制作了一个这样的示例文件

Contact

https://linkedin.com/1

Fugit dicta voluptates iusto. Aut nam iste impedit. A aliquam repellendus consectetur esse vero placeat doloremque. Necessitatibus est labore provident atque possimus

Page 1 of 2

Hic dignissimos consequatur error.

Contact

https://linkedin.com/2

Fugit dicta voluptates iusto. Aut nam iste impedit. A aliquam repellendus consectetur esse vero placeat doloremque. Necessitatibus est labore provident atque possimus. Hic dignissimos consequatur error.

，此测试输出

>>> for c in contacts:
...   print(c.splitlines())
... 
['', 'https://linkedin.com/1', '', 'Fugit dicta voluptates iusto. Aut nam iste impedit. A aliquam repellendus consectetur esse vero placeat doloremque. Necessitatibus est labore provident atque possimus', '', '', 'Hic dignissimos consequatur error.']
['', 'https://linkedin.com/2', '', 'Fugit dicta voluptates iusto. Aut nam iste impedit. A aliquam repellendus consectetur esse vero placeat doloremque. Necessitatibus est labore provident atque possimus. Hic dignissimos consequatur error.']

以一个联系方式计算单词，您可以通过位置访问

contacts[0].count("Biology")

Answer 2

这是一种具有更简单逻辑的解决方案，创建一个标志，该标志说明1。我们在联系人和2中。如果我们已经在此联系人中看到了该词。

counter = 0 
is_counted = True # Initialize the flag to avoid the code breaking
word = 'engineering' # Change this
with open('cv.txt','r') as file:
    line = file.readline()
    while line:
        if "contact" in line.lower():
            is_counted = False
        elif is_counted == False and word in line.lower():
            counter += 1
            is_counted = True
        line = file.readline()

print(counter)

我已经成功地在一个小样本上尝试了它，请在您的输入上尝试一下，看看它是否有效。