简单的功能组合类不起作用（缺少2个必需的位置参数）

Question

我目前正在研究数学，并试图构建一个简单的功能组成制造商

https://en.wikipedia.org /wiki/function_composition

我想告诉程序：

查看两个元组并比较它们：

tuple_1 = (2,4)
tuple_2 = (5,2)

do tuple_2 [1] and tuple_1 [0] [0]具有相同的价值？ （两个= 2）

如果是：

返回tuple（tuple_2 [0]）和tuple_1 [1]

5 4

我的功能工作：

list_of_tuples_1 = [
    (2,4),
    (2,5)    
    ]

list_of_tuples_2 = [
    (1,2),
    (5,2)
    ]

def give_function_composition(list_1, list_2):
    for tuples_2 in list_2:
        for tuples_1 in list_1:
            if tuples_2[1] == tuples_1[0]:
                return(str(tuples_2[0]) + " " + str(tuples_1[1]))

                
print(give_function_composition(list_of_tuples_1, list_of_tuples_2))

我的类不：

class Function_Composition():
    def __init__(self, list_1, list_2):
        self.list_1 = list_1
        self.list_2 = list_2
        
    def give_function_composition(self, list_1, list_2):
        for tuples_2 in list_2:
            for tuples_1 in list_1:
                if tuples_2[1] == tuples_1[0]:
                    return(str(tuples_2[0]) + " " + str(tuples_1[1]))        

                
my_set_1 = Function_Composition([(3,5),(1,5),(5,4)],
                                 [(5,7),(3,6),(1,8)])

print(my_set_1.give_function_composition())

TypeError: give_function_composition() missing 2 required positional arguments: 'list_1' and 'list_2'

这里有什么问题？我给了他两个清单，不是吗？

Answer 1

您应该参考传递到构造函数的实例数据，而不是两次传递在同一列表中：

class Function_Composition():
    def __init__(self, list_1, list_2):
        self.list_of_tuples_01 = list_1
        self.list_of_tuples_02 = list_2
        
    def give_function_composition(self):
        for tuples_2 in self.list_of_tuples_02:
            for tuples_1 in self.list_of_tuples_01:
                if tuples_2[1] == tuples_1[0]:
                    return(str(tuples_2[0]) + " " + str(tuples_1[1]))
        return "No relation found."

                
my_set_1 = Function_Composition([(3,5),(1,5),(5,4)],
                                 [(5,7),(3,6),(1,8)])

print(my_set_1.give_function_composition())

此输出：

No relation found.

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