“声明”阴影“参数”是什么意思。

发布于 2025-01-25 15:06:08 字数 532 浏览 3 评论 0原文

我正在尝试制作一个函数，以返回我将传递给它的整数号码的两倍。我在我的代码中收到以下错误消息：

声明'int x'阴影一个参数int x; “

这是我的代码：

#include <iostream>
int doublenumber();
using namespace std;
int doublenumber(int x)// <-- this is the function which returns double the value .
{
    int x;
    return 2 * x;
    cout << endl;
}
int main()
{
    int a;
    cout << "Enter the number that you want to double it : " << endl;
    cin >> a;
    doublenumber(a);

    return 0;
}

原文

I am trying to make a function that returns double the integer number that I will pass to it. I am getting the following error message with my code:

declaration of 'int x' shadows a parameter int x; "

Here is my code:

#include <iostream>
int doublenumber();
using namespace std;
int doublenumber(int x)// <-- this is the function which returns double the value .
{
    int x;
    return 2 * x;
    cout << endl;
}
int main()
{
    int a;
    cout << "Enter the number that you want to double it : " << endl;
    cin >> a;
    doublenumber(a);

    return 0;
}

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誰ツ都不明白 2025-02-01 15:06:08

您将X作为参数，然后尝试将其声明为本地变量，这是关于“阴影”的投诉所指的。

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假情假意假温柔 2025-02-01 15:06:08

我之所以这样做，是因为您的建议非常有帮助，这是最终结果：

#include <iostream>
using namespace std;

int doublenumber(int x)
{
    return 2*x;
}

int main()
{
    int a;
    cout << "Enter the number that you want to double it : " << endl;
    cin>>a;
    int n= doublenumber(a);
    cout << "the double value is : " << n << endl;
    return 0;
}

I did it because your advice was so helpful, and this is the final result :

#include <iostream>
using namespace std;

int doublenumber(int x)
{
    return 2*x;
}

int main()
{
    int a;
    cout << "Enter the number that you want to double it : " << endl;
    cin>>a;
    int n= doublenumber(a);
    cout << "the double value is : " << n << endl;
    return 0;
}

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書生途 2025-02-01 15:06:08

#include <iostream>
using namespace std;
int doublenumber(int x)
{
return 2*x;
}
int main()
{
int a;
cout << "Enter the number that you want to double it : " << endl;
cin>>a;
int d = doublenumber(a);

cout << "Double : " << d << endl;

return 0;
}

您的代码有一些问题。您的声明和功能定义死亡不匹配。因此，删除声明无需它。

您正在声明本地X变量内部函数，该函数将阴影您的函数参数。

#include <iostream>
using namespace std;
int doublenumber(int x)
{
return 2*x;
}
int main()
{
int a;
cout << "Enter the number that you want to double it : " << endl;
cin>>a;
int d = doublenumber(a);

cout << "Double : " << d << endl;

return 0;
}

There are some problem with your code. Your declaration and definition of function dies not match. So remove declaration as no necessity of it.

You are declaring local x variable inside function which will shadow your function arguments.

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