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如何等待事件所调用的函数的整个过程的完成？

发布于 2025-01-25 09:56:59 字数 81 浏览 4 评论 0原文

我有一个事件触发的函数，即使事件是其他时间触发的，是否有任何方法可以等待该功能的整个过程完成，因此只有在此之后它继续处理其他触发器收到的其他触发器？

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北座城市 2025-02-01 09:57:00

据我了解，您需要一些队列。您需要将事件推到那里，然后对它们进行处理。也许这样的东西：

const queue = [];

function eventHandler(event) {
  queue.push(event);
  if (queue.length === 1) {
    doTheJob();
  }
}
async function doTheJob() {
  if (queue.length > 0) {
    const event = queue[0]
    // do the job with the "event"
    await work1();
    await work2();
    await workN();
    queue.shift();
    doTheJob();
  }
}

As far as I understood you need some sort of a queue. You need to push events there and process them one by one. Maybe something like this:

const queue = [];

function eventHandler(event) {
  queue.push(event);
  if (queue.length === 1) {
    doTheJob();
  }
}
async function doTheJob() {
  if (queue.length > 0) {
    const event = queue[0]
    // do the job with the "event"
    await work1();
    await work2();
    await workN();
    queue.shift();
    doTheJob();
  }
}

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诗酒趁年少 2025-02-01 09:57:00

我设法找到了这样的解决方案：

var time = 1;
// SIMULATES THE ACTIVITIES OF THE EVENT
setInterval(async () => {

  await process();

}, 1000);

// THE PROCESSING THAT OCCURS WHEN THE EVENT IS TRIGGERED
async function process() {

  time += 4000
  const myPromise = await new Promise(async function (myResolve, myReject) {

    setTimeout(async () => {
      console.log(`Process executed`);
      myResolve("Process completed");
    }, time);

  });//End myPromise
  var result = await myPromise;
  time = time - 4000
}

I managed to find a solution like this:

var time = 1;
// SIMULATES THE ACTIVITIES OF THE EVENT
setInterval(async () => {

  await process();

}, 1000);

// THE PROCESSING THAT OCCURS WHEN THE EVENT IS TRIGGERED
async function process() {

  time += 4000
  const myPromise = await new Promise(async function (myResolve, myReject) {

    setTimeout(async () => {
      console.log(`Process executed`);
      myResolve("Process completed");
    }, time);

  });//End myPromise
  var result = await myPromise;
  time = time - 4000
}

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~没有更多了~