而循环不让我从标签中输入文字

Question

如果用户输入单词字符与随机生成的单词字符相同，我正在尝试打破循环。如果任何单词的字符与随机生成的单词字符都不匹配，则应在该标签中显示无与伦比的单词字符，然后跳过它并检查其余部分；然后，让用户再次尝试以最多6次猜测正确的单词。如果在上一次尝试循环中达到限制，则爆发。

我试图打破循环，但它不允许我从标签中输入，只是将上一个输入的用户保留在用户中，然后一次又一次地匹配。显示柜台为6次静置，它在显示匹配和无与伦比的字符上效果很好。

这是我的Java代码

try {
  BufferedReader reader = new BufferedReader(new FileReader("E:\\WordyGame\\src\\wordygame\\targetWords.txt"));
  String line = reader.readLine();
  List<String> words = new ArrayList<String> ();
  while (line != null) {
    String[] wordsLine = line.split(" ");
    for (String word: wordsLine) {
        words.add(word);
    }
    line = reader.readLine();

  }

  Random rand = new Random(System.currentTimeMillis());
  //getting random word from txt file
  String randomWord = words.get(rand.nextInt(words.size()));
  System.out.println("random word is : " + randomWord);
  String check_word = randomWord.trim().toLowerCase().toString();

  //getting user input from textfield

  //tp count limited attempts
  int count = 0;
  while (count<6) {
    String take_word = type_word.getText().toLowerCase().toString();
    System.out.println("user inpur is " + take_word);
    //dividing word into char and then each char to strings
    //user input word 
    char first = take_word.charAt(0);
    String first1 = String.valueOf(first);
    char second = take_word.charAt(1);
    String second1 = String.valueOf(second);
    char third = take_word.charAt(2);
    String third1 = String.valueOf(third);
    char fourth = take_word.charAt(3);
    String fourth1 = String.valueOf(fourth);
    char fifth = take_word.charAt(4);
    String fifth1 = String.valueOf(fifth);

    //random word from file

    char first2 = check_word.charAt(0);
    String first22 = String.valueOf(first2);
    char second2 = check_word.charAt(1);
    String second22 = String.valueOf(second2);
    char third2 = check_word.charAt(2);
    String third22 = String.valueOf(third2);
    char fourth2 = check_word.charAt(3);
    String fourth22 = String.valueOf(fourth2);
    char fifth2 = check_word.charAt(4);
    String fifth22 = String.valueOf(fifth2);

    if (take_word.length()<7) {
        if (first1.trim().equals(first22)) {
            word_1.setText(first1);
            word_1.setForeground(Color.red);

        } else {
            count++;
            JOptionPane.showMessageDialog(this, "Char 1 doesnt match");
            continue;
        }

        if (second1.trim().equals(second22)) {

            word_2.setText(second1);
            word_2.setForeground(Color.red);

        } else {
            count++;
            JOptionPane.showMessageDialog(this, "Char 2 doesnt match");
            continue;
        }
        if (third1.trim().equals(third22)) {

            word_3.setText(third1);
            word_3.setForeground(Color.red);

        } else {
            count++;
            JOptionPane.showMessageDialog(this, "Char 3 doesnt match");
            continue;
        }

        if (fourth1.trim().equals(fourth22)) {

            word_4.setText(fourth1);
            word_4.setForeground(Color.red);

        } else {

            count++;
            JOptionPane.showMessageDialog(this, "Char 4 doesnt match");
            continue;
        }
        if (fifth1.trim().equals(fifth22)) {

            word_5.setText(fifth1);
            word_5.setForeground(Color.red);
            //displaying charchter on GUI
            break;
        } else {
            JOptionPane.showMessageDialog(this, "doesnt 5 match");
            count++;
            continue;
        }

    } else {
        JOptionPane.showMessageDialog(this, "only 5 char word are allowed Number");
    }

    if (check_word.trim().equals(take_word)) {
        JOptionPane.showMessageDialog(this, "YOU guessed the number in first attempt");
        break;
    } else {
        count++;
    }

  }

  System.out.println(count);
} catch (Exception e) {
  System.out.println(e);
}