SPARQL-如何仅获得最新实体
在我的三重商店中,我有一个具有属性架构:版本和架构:datecreated的schema:Creativework的集合。 现在,我想获得所有架构:创意工作,但只有最新的架构。 我的示例:
PREFIX schema: <https://schema.org/>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
SELECT DISTINCT *
WHERE {
?subject rdf:type schema:CreativeWork .
?subject schema:identifier ?identifier .
?subject schema:version ?version .
?subject schema:dateCreated ?dateCreated .
OPTIONAL {?subject schema:about/schema:name ?name .}
FILTER( ?identifier = "46d8b7abfec44865a567ea04e385661b" ) .
} LIMIT 10
如何仅查询最新版本?
可执行示例: https://api.triplipliplipliplipliplipliplydb.com/s/rllq4v-jgs
注意:filter(?didentifier =“ 46D8B7ABFEC44865A567EA04E385661B”)。
只是为了使其更容易。
In my triple store i've a collection of schema:CreativeWork which has the property schema:version and schema:dateCreated.
Now i want to get all schema:CreativeWork but only the newest ones.
My sample:
PREFIX schema: <https://schema.org/>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
SELECT DISTINCT *
WHERE {
?subject rdf:type schema:CreativeWork .
?subject schema:identifier ?identifier .
?subject schema:version ?version .
?subject schema:dateCreated ?dateCreated .
OPTIONAL {?subject schema:about/schema:name ?name .}
FILTER( ?identifier = "46d8b7abfec44865a567ea04e385661b" ) .
} LIMIT 10
How do i manage to query only the latest version?
executable sample: https://api.triplydb.com/s/rLq4V-JgS
Note: FILTER( ?identifier = "46d8b7abfec44865a567ea04e385661b" ) .
is just to make it easier.
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Unformeduser的查询运作良好:
The query of UninformedUser is working well: