内容uri上的outputStream

发布于 2025-01-24 18:17:09 字数 2356 浏览 0 评论 0原文

我拥有特定用户选择的图像的内容URI，我想在其上打开一个InputStream，以便

在用户选择图像时从该URI中获取位图，我将持久的读取和写入权限：

val flags = Intent.FLAG_GRANT_READ_URI_PERMISSION or Intent.FLAG_GRANT_WRITE_URI_PERMISSION
contentResolver?.takePersistableUriPermission(mediaUri, flags)

内容URI在这种格式：content：//com.android.providers.downloads.documents/document/msf%3a24

获得此InputStream的最佳解决方案似乎是：

val inputFile = context.contentResolver.openInputStream(uri)
val bitmap = BitmapFactory.decodeStream(inputFile)

运行第二行的第二行时，会出现错误代码：

E/BitmapFactory: Unable to decode stream: java.io.FileNotFoundException: /com.android.providers.downloads.documents/document/msf%3A24: open failed: ENOENT (No such file or directory)

请注意，URI似乎在错误消息中畸形，

我该如何获取输入流？

附录：我正在尝试在工人（androidx.work.coroutineworker）中获取此输入流。

用户选择图像： https://github.com/ninjinskii/cavity/cavity/blob/master/master/papp/src/src/main/java/java/java/com/com/louis/louis/app/cavity/cavity/cavity/ui/ui/addwine/addwine/ddwine/fragmentaddwindwindwwine.kt-l53一下

图像URI存储在DB中： https://github.com/ninjinskii/ninjinskii/cavity/cavity/cavity/blob/blob/master/src/src/src/main/main/java/java/java/java/com/com/com/louis/louis/louis/louis/app/app/cavity/ui-ui-ui-ui /addwine/addwineviewmodel.kt#l86

用户触发负责图像上传的工作者： https://github.com/ninjinskii/cavity/cavity/blob/blob/feature/backup-api/backup-appi/src/src/src/main/java/java/java/comcom/louis/louis/louis/app/cavity/cavity/ui/ui/ui/ui/ui/acccount/， Worker/uploadworker.kt＃l131

原文

I have the content URI of a specific user selected image on which i want to open an InputStream, in order to get a Bitmap from that URI

When the user select the image, i take the persistable read and write permissions:

val flags = Intent.FLAG_GRANT_READ_URI_PERMISSION or Intent.FLAG_GRANT_WRITE_URI_PERMISSION
contentResolver?.takePersistableUriPermission(mediaUri, flags)

The content URI is in this format: content://com.android.providers.downloads.documents/document/msf%3A24

The best solution to get this InputStream seems to be:

val inputFile = context.contentResolver.openInputStream(uri)
val bitmap = BitmapFactory.decodeStream(inputFile)

An error is thrown when running the second line of code:

E/BitmapFactory: Unable to decode stream: java.io.FileNotFoundException: /com.android.providers.downloads.documents/document/msf%3A24: open failed: ENOENT (No such file or directory)

Note that the URI seems to malformed in the error message

How can i get my InputStream ?

Addendum: I'm trying to get this InputStream in a Worker (androidx.work.CoroutineWorker).

User selects the image: https://github.com/ninjinskii/Cavity/blob/master/app/src/main/java/com/louis/app/cavity/ui/addwine/FragmentAddWine.kt#L53

The image URI is stored in the DB: https://github.com/ninjinskii/Cavity/blob/master/app/src/main/java/com/louis/app/cavity/ui/addwine/AddWineViewModel.kt#L86

User trigger the WorkManager in charge for image uploading:
https://github.com/ninjinskii/Cavity/blob/feature/backup-api/app/src/main/java/com/louis/app/cavity/ui/account/worker/UploadWorker.kt#L131

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