AngularJS控制器内部工厂的不同依赖注入

Question

假设我有多个工厂，这些工厂内部具有相同的功能和变量。例如，

var app = angular.module('app', []);
app.factory('employerFactory', function () {
        return {
            firstName: 'Kristoffer',
            lastName: 'Karlsson',
        };
    });
app.factory('employeeFactory', function () {
        return {
            firstName: 'Alice',
            lastName: 'Guo',
        };
    });

现在我有了这样的控制器：

app.controller('MyController', function($scope, myFactory) {
    $scope.firstName = myFactory.firstName;
    $scope.lastName = myFactory.lastName; 
 });

我的问题是如何启动两个控制器，一个是在雇主中通过依赖性，另一个是雇员。我知道RouterProvider可以帮助将不同的控制器路由不同的URL路由。我可以操纵它以将不同的工厂传递到控制器中吗？类似

$routeProvider.
  when('/a', {
    templateUrl: 'test.html',
    controller: 'MyController' // should get passed factory 'employerFactory'
  }).
  when('/b', {
    templateUrl: 'test.html',
    controller: 'MyController' // should get passed factory 'employeeFactory'
});

Answer 1

只需将服务用作额外的层来处理交换逻辑，在其中注入两个工厂，然后创建方法来处理共同功能：

app.service('FactoryService', function($scope, employerFactory, employeeFactory) {
   var _mode = 0;
   var _factories = [employerFactory, employeeFactory];
   return {
      setMode: function(mode) {
         _mode = mode % (_factories.length - 1);// possibly 0 | 1 in this case, but inject as many factories as you wish
      },
      getFirstName: function() {
         return _factories[_mode].firstName;
      },
      getLastName: function() {
         return _factories[_mode].lastName;
      }
   }
 });

最后将其注入控制器，并调用其方法，然后

app.controller('MyController', function($scope, FactoryService) {

    // select the first factory (employerFactory)
    FactoryService.setMode(0);
    $scope.firstName = FactoryService.getFirstName();
    $scope.lastName = FactoryService.getLastName(); 
    console.log( $scope.firstName, $scope.lastName); 

    // select the second factory (employeeFactory)
    FactoryService.setMode(1);
    $scope.firstName = FactoryService.getFirstName();
    $scope.lastName = FactoryService.getLastName(); 
    console.log( $scope.firstName, $scope.lastName); 
 });

根据您想要的任何方法， ，这只是它如何工作的一个例子。